Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(11, 12, 13, 14) = #₁!₂!3!₁! Find (0.3) ¹ (0.1) 2 (0.4) ³ (0.2) 4 x₁ + x₂ + 3 + ₁ = 20 (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1₁ = 4, X3 = 6]
Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(11, 12, 13, 14) = #₁!₂!3!₁! Find (0.3) ¹ (0.1) 2 (0.4) ³ (0.2) 4 x₁ + x₂ + 3 + ₁ = 20 (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1₁ = 4, X3 = 6]
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![(18) Let X = (X₁, X2, X3, X₁)' have probability distribution function
20!
f(x1, 12, 13, 14)
æılæşlæşlæ₁! (0.3)²¹ (0.1) ³² (0.4) ³³ (0.2)³¹ T₁+T₂ + 3 + ₁ = 20
Find
(i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4)
(ii) E [X2, X₁ X1 = 4, X3 = 6]
(iii) the distribution of Z = X₁ + 4X2 - 2X3 + x4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffc42a076-5c06-46af-a63c-d94f125ca0b9%2F6ff8b2ca-e68b-418f-9975-e0cdc512ad86%2Fqjw0vo5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(18) Let X = (X₁, X2, X3, X₁)' have probability distribution function
20!
f(x1, 12, 13, 14)
æılæşlæşlæ₁! (0.3)²¹ (0.1) ³² (0.4) ³³ (0.2)³¹ T₁+T₂ + 3 + ₁ = 20
Find
(i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4)
(ii) E [X2, X₁ X1 = 4, X3 = 6]
(iii) the distribution of Z = X₁ + 4X2 - 2X3 + x4
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