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Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(11, 12, 13, 14) = #₁!₂!3!₁! Find (0.3) ¹ (0.1) 2 (0.4) ³ (0.2) 4 x₁ + x₂ + 3 + ₁ = 20 (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1₁ = 4, X3 = 6]

Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(11, 12, 13, 14) = #₁!₂!3!₁! Find (0.3) ¹ (0.1) 2 (0.4) ³ (0.2) 4 x₁ + x₂ + 3 + ₁ = 20 (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1₁ = 4, X3 = 6]

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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(18) Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(x1, 12, 13, 14) æılæşlæşlæ₁! (0.3)²¹ (0.1) ³² (0.4) ³³ (0.2)³¹ T₁+T₂ + 3 + ₁ = 20 Find (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1 = 4, X3 = 6] (iii) the distribution of Z = X₁ + 4X2 - 2X3 + x4
Transcribed Image Text:(18) Let X = (X₁, X2, X3, X₁)' have probability distribution function 20! f(x1, 12, 13, 14) æılæşlæşlæ₁! (0.3)²¹ (0.1) ³² (0.4) ³³ (0.2)³¹ T₁+T₂ + 3 + ₁ = 20 Find (i) Pr(X₁ = 6, X2 = 2, X3 = 8, X₁ = 4) (ii) E [X2, X₁ X1 = 4, X3 = 6] (iii) the distribution of Z = X₁ + 4X2 - 2X3 + x4
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