Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the minimum has a Weibull distribution with parameters a = 2 and B = 1.5. (a) What is the cdf of X? x< 5.5 F(x) = { x2 5.5 (b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 5.5) and V(X - 5.5).] (Round your answers to three decimal places.) E(X) = V(X) =| 10-1 weeks (10-1 weeks)? (c) Compute P(X > 7). (Round your answer to four decimal places.) (d) Compute P(7 SXS 8.5). (Round your answer to four decimal places.)

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Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the minimum has a Weibull distribution with parameters a = 2 and B = 1.5.
(a) What is the cdf of X?
x< 5.5
F(x) = {
x2 5.5
(b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 5.5) and V(X - 5.5).] (Round your answers to three decimal places.)
E(X) =
V(X) =|
10-1 weeks
(10-1 weeks)?
(c) Compute P(X > 7). (Round your answer to four decimal places.)
(d) Compute P(7 SXS 8.5). (Round your answer to four decimal places.)
Transcribed Image Text:Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 5.5 and that the excess X - 5.5 over the minimum has a Weibull distribution with parameters a = 2 and B = 1.5. (a) What is the cdf of X? x< 5.5 F(x) = { x2 5.5 (b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 5.5) and V(X - 5.5).] (Round your answers to three decimal places.) E(X) = V(X) =| 10-1 weeks (10-1 weeks)? (c) Compute P(X > 7). (Round your answer to four decimal places.) (d) Compute P(7 SXS 8.5). (Round your answer to four decimal places.)
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