Let X = the time (in 10 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 6.5 and that the excess X - 6.5 over the minimum has a Weibull distribution with parameters a = 2 and ß = 2.5. (a) What is the cdf of X? F(x) = 0 + 1 --((-65)²) e x <6.5 x ≥ 6.5 (b) What are the expected return time and variance of return time? [Hint: First obtain E(X- 6.5) and V(X- 6.5).] (Round your answers to three decimal places.) E(X)= 10-1 weeks V(x)= (10-1 weeks)2 (c) Compute P(X> 9). (Round your answer to four decimal places.) (d) Compute P(9 ≤ x ≤ 11.5). (Round your answer to four decimal places.)

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Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 6.5 and that the excess X - 6.5 over the
minimum has a Weibull distribution with parameters a = 2 and ß = 2.5.
(a) What is the cdf of X?
0
F(x) =
1-e
(*-6-5) ²)
x 6.5
x ≥ 6.5
(b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 6.5) and V(X- 6.5).] (Round your answers to three decimal places.)
E(X) =
10-¹ weeks
V(X) =
(10-¹ weeks)²
(c) Compute P(X> 9). (Round your answer to four decimal places.)
(d) Compute P(9 ≤ x ≤ 11.5). (Round your answer to four decimal places.)
Transcribed Image Text:Let X = the time (in 10-1 weeks) from shipment of a defective product until the customer returns the product. Suppose that the minimum return time is y = 6.5 and that the excess X - 6.5 over the minimum has a Weibull distribution with parameters a = 2 and ß = 2.5. (a) What is the cdf of X? 0 F(x) = 1-e (*-6-5) ²) x 6.5 x ≥ 6.5 (b) What are the expected return time and variance of return time? [Hint: First obtain E(X - 6.5) and V(X- 6.5).] (Round your answers to three decimal places.) E(X) = 10-¹ weeks V(X) = (10-¹ weeks)² (c) Compute P(X> 9). (Round your answer to four decimal places.) (d) Compute P(9 ≤ x ≤ 11.5). (Round your answer to four decimal places.)
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