Let x (t) = 5 cos (2π(400)t +0.5π) + 10 cos(2π(600)t – 0.5π). Thesignal x(t) is sampled at fs 1000Hz to get=x[n] = x(nTs) = A cos(ŵn + 6) where fs = . Find A, w, and .O A = 5ŵ=6:none of the aboveû =O A = 154TT50.5TФ2πT5-0.5пФO A = 15w = 2T50.5T==

here we have to find the sampled signal.

Let x (t) = 5 cos(2π(400)t +0.5π) + 10 cos(2π(600)t – 0.5π). The = 1000Hz to get signal ä(t) is sampled at fs x[n] = x(nTs) = A cos(ŵn + 6) where fs = 1⁄. Find A, w, and p. O A=5 w = 2/5 ф = -0.5п O none of the above O A = 15 w = 4T p=0.5T O A = 15 ŵ= 24 $ = 0.5T

Let x (t) = 5 cos(2π(400)t +0.5π) + 10 cos(2π(600)t – 0.5π). The = 1000Hz to get signal ä(t) is sampled at fs x[n] = x(nTs) = A cos(ŵn + 6) where fs = 1⁄. Find A, w, and p. O A=5 w = 2/5 ф = -0.5п O none of the above O A = 15 w = 4T p=0.5T O A = 15 ŵ= 24 $ = 0.5T

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Let x (t) = 5 cos (2π(400)t +0.5π) + 10 cos(2π(600)t – 0.5π). The
signal x(t) is sampled at fs 1000Hz to get
=
x[n] = x(nTs) = A cos(ŵn + 6) where fs = . Find A, w, and .
O A = 5
ŵ
=
6:
none of the above
û =
O A = 15
4TT
5
0.5T
Ф
2πT
5
-0.5п
Ф
O A = 15
w = 2T
5
0.5T
=
=

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