Let X represent the width and Y represent the length of rectangular panels used for interior doors (in inches). Suppose X is normally distributed with a mean of 20 inches and standard deviation of 1.2 inches, and Y is normally distributed with a mean of 4 inches and a standard deviation of 0.65 inches. Furthermore, the covariance between X and Y is 0.325. Consider the perimeter of a panel - that is, consider 2 X+2 Y Which of the computations below is the proper way to calculate the variance? OA. V(2X+2Y) = (2)(1.2)2+(2)(0.65)2+(2)(2)(2)(0.325) OB. V(2X + 2Y) = (2)(1.2)2+(2)(0.65)2 + 0.325 OC. V(2x + 2Y) = (4)(1.2)2 + (4)(0.65)2 + (2)(2)(2)(0.325) OD. V(2X+2Y)= (4)(1.2)2 + (4)(0.65)2 + 0.325

MATLAB: An Introduction with Applications
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QUESTION 14
Let X represent the width and Y represent the length of rectangular panels used for interior doors (in inches). Suppose X is normally distributed with a mean of 20 inches and standard deviation of 1.2 inches, and Y is normally
distributed with a mean of 4 inches and a standard deviation of 0.65 inches. Furthermore, the covariance between X and Y is 0.325. Consider the perimeter of a panel - that is, consider 2 X+2 Y.
Which of the computations below is the proper way to calculate the variance?
O A. V(2X + 2Y) = (2)(1.2)2 + (2)(0.65)2 + (2)(2)(2)(0.325)
O B. V(2X + 2Y) = (2)(1.2)2+(2)(0.65)2 + 0.325
OC. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2+(2)(2)(2)(0.325)
O D. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2 +0.325
Transcribed Image Text:QUESTION 14 Let X represent the width and Y represent the length of rectangular panels used for interior doors (in inches). Suppose X is normally distributed with a mean of 20 inches and standard deviation of 1.2 inches, and Y is normally distributed with a mean of 4 inches and a standard deviation of 0.65 inches. Furthermore, the covariance between X and Y is 0.325. Consider the perimeter of a panel - that is, consider 2 X+2 Y. Which of the computations below is the proper way to calculate the variance? O A. V(2X + 2Y) = (2)(1.2)2 + (2)(0.65)2 + (2)(2)(2)(0.325) O B. V(2X + 2Y) = (2)(1.2)2+(2)(0.65)2 + 0.325 OC. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2+(2)(2)(2)(0.325) O D. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2 +0.325
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