Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with u = 110.4 ft and o = 46.4 ft. You intend to measure a random sample of n = 219 trees. What is the mean of the distribution of sample means? What is the standard deviation of the distribution of sample means (i.e., the standard error in estimating the mean)? (Report answer accurate to 2 decimal places.)
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- Let XX represent the full length of a certain species of newt. Assume that XX has a normal probability distribution with mean 195.5 inches and standard deviation 5.5 inches.You intend to measure a random sample of n=141n=141 newts. The bell curve below represents the distibution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places.Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with mean 225.2 ft and standard deviation 67.3 ft. 207 trees. You intend to measure a random sample of n = The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error (standard deviation) of the sampling distribution. Complete the indicated boxes, correct to two decimal places.Two normal distributions are compared. One has a mean of 10 and a standard deviation of 10. The second normal distribution has a mean of 10 and a standard deviation of 2. Which of the following is true? The dispersions of the distributions are different. The dispersions of the distributions are the same. The distributions are from two different families of distributions. The locations of the distributions are different.
- Given a normal distribution with mean of 14 & standard deviation of 2. What is the P (13 ≤ x ≤ 15)? Write every rule you are going to useUse the Central Limit Theorem to find the mean and standard error of the mean of the sampling distribution. Then sketch a graph of the sampling distribution. The mean price of photo printers on a website is $229 with a standard deviation of $63. Random samples of size 24 are drawn from this population and the mean of each sample is determined. The mean of the distribution of sample means isSuppose that the weight of seedless watermelons is normally distributed with mean 6.2 kg. and standard deviation 1.5 kg. Let X be the weight of a randomly selected seedless watermelon. Round all answers to two decimal places. A. X ~ N( , ) B. What is the median seedless watermelon weight? kg. C. What is the Z-score for a seedless watermelon weighing 8 kg? D. What is the probability that a randomly selected watermelon will weigh more than 7 kg? E. What is the probability that a randomly selected seedless watermelon will weigh between 4 and 5 kg? F. The 80th percentile for the weight of seedless watermelons is kg.
- In a population of a certain species of newt, the mean length of the newts is μ= 63 inches and the standard deviation is σ= 3.4 inches. You collect a random sample of n=16 newts. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. mean of distribution= standard error= Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.Chebyshev's Theorem states that for any distribution of numerical data, at least 1-1/k? of the numbers lie within The percent of numbers between 88 and 112 is at least %. k standard deviations of the mean. (Round to the nearest hundredth as needed.) In a certain distribution of numbers, the mean is 100, with a standard deviation of 6. Use Chebyshev's Theorem to tell what percent of the numbers are between 88 and 112.The weights of cans of Ocean brand tuna are supposed to have a net weight of 6 ounces. The manufacturer tells you that the net weight is actually a Normal random variable with a mean of 5.95 ounces and a standard deviation of 0.2 ounces. Suppose that you draw a random sample of 42 cans. Parti) Suppose the number of cans drawn is doubled. How will the standard deviation sample mean weight change? A. It will decrease by a factor of √2. B. It will increase by a factor of √2. C. It will increase by a factor of 2. D. It will decrease by a factor of 2. E. It will remain unchanged. Part ii) Suppose the number of cans drawn is doubled. How will the mean of the sample mean weight change? ▸ A. It will increase by a factor of √2. B. It will decrease by a factor of 2. C. It will increase by a factor of 2. D. It will decrease by a factor of √2. E. It will remain unchanged. Part iii) Consider the statement: The distribution of the mean weight of the sampled cans of Ocean brand tuna is Normal." A. It…
- Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with mean 151.4 ft and standard deviation 21.9 ft. You intend to measure a random sample of n = 126 trees. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error (standard deviation) of the sampling distribution. Complete the indicated boxes, correct to two decimal places. Submit Question up Ce 23 & 6 8. e y f ge diLet XX represent the full length of a certain species of newt. Assume that XX has a normal probability distribution with mean 51.3 inches and standard deviation 5.4 inches.You intend to measure a random sample of n=110n=110 newts. The bell curve below represents the distibution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places.Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with mean 182.5 ft and standard deviation 59.9 ft.You intend to measure a random sample of n=79n=79 trees. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error (standard deviation) of the sampling distribution. Complete the indicated boxes, correct to two decimal places.