Exercise 3Suppose a new drug is available for treating high blood pressure. We want to investigateits effect by running a controlled experiment:• We randomly select some patients with high blood pressure and randomly divide theminto two groups, Group A and Group B.1• We then give the actual drug to patients in Group A and a placebo (i.e. non-harmfulfake drug) to patients in Group B.Let X be the amount of blood pressure reduction in a patient taking the new drug, andY the amount of blood pressure reduction in a patient taking the placebo. Assume thatX ~ Nux, 12) and Y N(μy, 8). How many patients (in total) do we need to selectfor participation in this experiment, if we want to construct a 95% confidence interval forx-μy with length < 2?

Given that X~N(μx, 12) and Y~N(μy, 8) length of 95% C.I.≤2. Note we have to assume that the…

Answered: Let X be the amount of blood pressure…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Currently patrons at the library speak at an average of 61 decibels. Will this average decline after the installation of a new computer plug in station? After the plug in station was built, the librarian randomly recorded 57 people speaking at the library. Their average decibel level was 58 and their standard deviation was 10. What can be concluded at the the αα = 0.10 level of significance? For this study, we should use t-test for population mean The null and alternative hypotheses would be: H0:H0: Incorrect >, <, = or not equal to also provide the __?__ H1:H1: Incorrect >,<, = or not equal to also provide the __?__ The test statistic tc =(please show your answer to 3 decimal places.) The p-value = __?__ (Please show your answer to 4 decimal places.) e.Thus, the final conclusion is that .. a. The data suggest the populaton mean has significantly decreased from 61 at αα = 0.10, so there is statistically significant evidence…
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The scores for a certain standardized test have a population mean of μ=285 with a population standard deviation σ=125. You take an SRS of size 400 find that the sample mean \bar x is 288. The margin of error in a 90% confidence interval for μ based on this sample is
Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of µ = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of - = 7.3 ppb arsenic. It is known that o = information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical 1.9ppb for this type of data. Does this approach. Use a = 0.01 What is the criterion (step 3) for this problem? 2.33 or more 1.645 or more -2.33 or less -1.645 or less
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Please solve by using R calculator or excel. Show all work.
Lian wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. She randomly selects a sample of 45 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 19.7 and a standard deviation of 38 What is the 95% confidence interval for the number of chocolate chips per cookie for Big Chip co possible okies? Assume the data is from a normally distributed population. Round answers to 3 decimal places where
11% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 344 people from the inner city surveyed, 34 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? The test statistic= (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
We want to estimate the number of pounds of ground beef produced during a month. The firm processes 25,000 cows every year in this plant, and samples 500 cows for this investigation. This sample produced i = 290 lbs ground of beef per cow with a sample standard deviation of s = 40 lbs. The plant is paid S.75/b for the beef. a) Find a 90% confidence interval for ground beef. The plant manager bragged about the productivity of his workers and gave them a bonus because he says they slaughtered 2,500 cows and made $560,000 for the plant this month. Should the board of directors investigate? Why or why not? b) Type here to search 8. 9. E R T Y D F G K L ent pause V B M alt ctri
Check my An airline's data indicate that this past year, the average time it takes to board their flights is 45 minutes. The airline is considering changing their boarding procedures to reduce the boarding time for travelers. The new procedures were implemented and the boarding times for a random sample of 22 customers was taken to determine if there was a statistically significant decrease at in boarding times a= 0.10 with z = - 0.89 and t = . 1.07. What is the decision?
A certain counselor wants to compare mean IQ scores for two different social groups. A random sample of 15 IQ scores from group 1 showed a mean of 117 and a standard deviation of 17 , while an independently chosen random sample of 9 IQ scores from group 2 showed a mean of 112 and a standard deviation of 15 . Assuming that the populations of IQ scores are normally distributed for each of the groups and that the variances of these populations are equal, construct a 90% confidence intervalfor the difference −μ1μ2 between the mean μ1 of IQ scores of group 1 and the mean μ2 of IQ scores of group 2 . Then find the lower limit and upper limit of the 90% confidence interval. Carry your intermediate computations to at least three decimal places. Round your responses to at least two decimal places. (If necessary, consult a list of formulas.)
A sample of size 31 was gathered from high school seniors to estimate how many intended to attend the state university. It is known that the proportion of the population answering "yes" was 0.7. What are the mean and standard deviation, and standard error of the mean of this sample? mean = E(p) = %3D standard error = SD(p) (accurate to 3 decimal places)

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