Let X be a strictly positive r.v. with the following moment generating function:MX (t) = 1/(1 − 2t)^3(a) Use Markov’s inequality to find an upper bound for P (|X| ≥ 18).(b) Use Chebyshev’s inequality to find an upper bound for P (|X − 6| ≥ 12).(c) Find the lowest possible upper bound for P (X ≥ 18) you could get fromChernoff’s inequality.

Let X be a strictly positive r.v. with the following moment generating function:MX (t) = 1/(1 − 2t)^3(a) Use Markov’s inequality to find an upper bound for P (|X| ≥ 18).(b) Use Chebyshev’s inequality to find an upper bound for P (|X − 6| ≥ 12).(c) Find the lowest possible upper bound for P (X ≥ 18) you could get fromChernoff’s inequality.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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