Let X be a random variable with the following probability distribution: X f(x) -2 0.5 3 0.3 Find the standard deviation of X. The standard deviation is 5 0.2 4 ... (Round to two decimal places as needed.)

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18. Please answer the following question.
**Probability Distribution and Standard Deviation Calculation**

Let \( X \) be a random variable with the following probability distribution:

\[
\begin{array}{c|ccc}
x & -2 & 3 & 5 \\
\hline
f(x) & 0.5 & 0.3 & 0.2 \\
\end{array}
\]

**Task:** Find the standard deviation of \( X \).

---

**Solution:**

1. **Mean Calculation (\(\mu\)):**

   \[
   \mu = \sum (x \cdot f(x)) = (-2 \cdot 0.5) + (3 \cdot 0.3) + (5 \cdot 0.2)
   \]

2. **Variance Calculation (\(\sigma^2\)):**

   \[
   \sigma^2 = \sum ((x - \mu)^2 \cdot f(x))
   \]

3. **Standard Deviation (\(\sigma\)):**

   \[
   \sigma = \sqrt{\sigma^2}
   \]

Round the final answer to two decimal places as needed.

**Final Answer:**

The standard deviation is \(\Box\). (Round to two decimal places as needed.)
Transcribed Image Text:**Probability Distribution and Standard Deviation Calculation** Let \( X \) be a random variable with the following probability distribution: \[ \begin{array}{c|ccc} x & -2 & 3 & 5 \\ \hline f(x) & 0.5 & 0.3 & 0.2 \\ \end{array} \] **Task:** Find the standard deviation of \( X \). --- **Solution:** 1. **Mean Calculation (\(\mu\)):** \[ \mu = \sum (x \cdot f(x)) = (-2 \cdot 0.5) + (3 \cdot 0.3) + (5 \cdot 0.2) \] 2. **Variance Calculation (\(\sigma^2\)):** \[ \sigma^2 = \sum ((x - \mu)^2 \cdot f(x)) \] 3. **Standard Deviation (\(\sigma\)):** \[ \sigma = \sqrt{\sigma^2} \] Round the final answer to two decimal places as needed. **Final Answer:** The standard deviation is \(\Box\). (Round to two decimal places as needed.)
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