Let X be a r.v. with mean 4 and variance 5. Find an upper bound forP (X − 4 ≥ 8 ∪ X − 4 ≤ −8). (Hint: The condition that one inequality holds OR the otherholds can be combined into a single inequality via absolute value.)
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Let X be a r.v. with
P (X − 4 ≥ 8 ∪ X − 4 ≤ −8). (Hint: The condition that one inequality holds OR the other
holds can be combined into a single inequality via absolute value.)
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- The following two-by-two table was created from the data. TROUBLE STAYING ASLEEP [outcome] TROUBLE FALLING ASLEEP[predictor] Yes No TOTAL Yes 65 40 105 No 51 110 161 TOTAL 116 150 266 Let TP denote True Positive cases. Let TN denote True Negative cases. Let FP denote False Positive cases. Let FN denote False Negative cases. Trouble staying asleep (outcome) Yes No Trouble falling asleep (predictor) Yes TP FN No FP TN What is the positive predictive value of the predictor variable for the outcome? What is the negative predictive value of the predictor variable for the outcome? Which predictive value (negative or positive) is higher? What proportion of participants have trouble falling asleep and staying asleep? What is the prevalence of “Trouble staying asleep” among study participants?I need the answer as soon as possibleA sample of 350 Mathematicians is selected and several variables are recorded. Which of the following statements is correct? Mathematician's monthly income is a ratio level data. Socioeconomic status (recorded as “low income”, “middle income”, or “high income" is nominal level data. The number of field or subject of specialization is a continuous variable. The primary field of study is ordinal level data.
- The boxplot shown below results from the heights (cm) of males listed in a data set. What do the numbers in that boxplot tell us? 154 173.8 194 169.7 183.5 The minimum height is cm, the first quartile Q, is cm, the second quartile Q, (or the median) is cm, the third quartile Q, is cm, and the maximum height is cm. (Type integers or decimals. Do not round,)The graph portrays the decision criterion for a hypothesis test for a population mean. The null hypothesis is H:u=µ. The curve is the normal curve for the test statistic under the assumption that the null hypothesis is true. Use the graph to solve the problem. A graphical display of the decision criterion follows. do 0.9 Do not reject H Reject H, 0.8- 0.7- 0.6- 05- 04 0.3- 0.2- 0.1- !0.014 -059 0.59 L18 137 236 295 3.54 2.197 Determine the rejection region. O0.014 02.197 O All z-scores that lie to the right of 2.197 OAll 2-scores that lie to the left of 2.197Let X1, X2,..., X3 denote a random sample from a population having mean u and variance o?... Which of the estimators have a variance of 7 X1+X2++X, 7 2X1-X6+X4 2 3X1-X3+X4 2 2(X1+X2+.+X¬) 4 7
- Plz answer the question in 10 minutes plzzz and get thumb up plzzzzResearchers collected data on the numbers of hospital admissions resulting from motor vehicle crashes, and results are given for Friday the 6th and Friday the 13th in the same month. Use the Wilcoxon signed-ranks test to test the claim that the matched pairs have differences that come from a population with median equal to zero at a significance level of α = 0.1. Fri. 6th 14 Fri. 13th 14 14 8 9 11 11 13 7 8 5 5 Click to view a table of critical values for the Wilcoxon signed-ranks test. 8 D First define the null and alternative hypotheses. Ho: The population of differences has a median equal to 0. H₁: Calculate the test statistic. T=0 Calculate the critical value. The critical value is. What is the conclusion for this hypothesis test? O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim of no difference. O B. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim of no difference. O C. Reject Ho. There is insufficient evidence to…Assume that a sample is used to estimate a population mean u. Find the 99% confidence interval for a sample of size 376 with a mean of 16.8 and a standard deviation of 15.9. Enter your answer as a tri-linear inequality accurate to 3 decimal places.3. An integer is randomly chosen from the set 1, 2,..., 100. If this integer is divisible by 2 we let Y = 0, and if it is not divisible by 2 but is divisible by 3 then Y = 1. We let Y = 2 in all other cases. Find mean and variance of Y.Suppose that a researcher is interested in the average standardized test score for fifth graders in a local school district. The fifth graders at a specific school would comprise a ___________ and their average test score would be a ___________.In order to use the defining formula for variance, we must calculate (x − x)2 for each data value in the data set 14, 18, 22, 26, 33. Use the values in the data set and the mean x = 22.6 to fill out the following table. x 14 18 22 26 33 x 22.6 22.6 22.6 22.6 22.6 x − x 14 − 22.6 = −8.6 18 − 22.6 = __________ 22 − 22.6 = −0.6 26 − 22.6 = _________ 33 − 22.6 = 10.4 (x − x)2 73.96 __________ 0.36 ________ 108.16SEE MORE QUESTIONS
