Let X be a normal random variable with mean 33 and standarddeviation 4.02. Find c such that P(33-c < X < 33+c)=0.515.Round your answer to 4 decimal places.H+c

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Answered: Let X be a normal random variable with…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A population of values has a normal distribution with μ=204.6μ=204.6 and σ=17σ=17. You intend to draw a random sample of size n=92n=92.Find P67, which is the score separating the bottom 67% scores from the top 33% scores.P67 (for single values) = IncorrectFind P67, which is the mean separating the bottom 67% means from the top 33% means.P67 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
B.202 ul X с Too Weekly w sal Success C X Bb Exam 2 X Bb Take Test: Bb UTF-8 Ass Question Completion Status: nccu.blackboard.com/webapps/assessment/take/launch.jsp?course_assessment_id=_26 http: QUESTION 8 For any continuous random variable, the probability that the random variable takes a value less than zero a. is any number between zero and one. b. is more than one, since it is continuous. c. is a value larger than zero. d. is zero. QUESTION 9 For the standard normal probability distribution, the area to the right of the mean is a. 1. b. 3.09.
Use the Suppose in a local Kindergarten through 12th grade (K -12) school district, 42% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. nd the mean and the standard deviation of X of B(144, 0.42). Round off to 4 decimal places. b. Now approximate X of B(144, 0.42) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y N( C Find the probability that at most 72 favor a charter school using the normal approximation and the table. Round off to z-values up to 2 decimal places.) P(X 68) P(Y > ~ (Z >) e. Find the probability that exactly 63 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 63) P(
where appropriate. 1. Experience has shown that the seeds from a certain variety of orchid have a 75% chance of germinating when planted under normal conditions. Suppose n seeds are planted, and let X be the random variable that counts the number of seeds that germinate. (a) What type of random variable is X? Indicate both the type and the appropriate parameters using the "~" notation. Write down the pmf of X, and do not forget to indicate the range of values that x can take on. X ~ px (x) = = (b) What is the minimum value of n so that the probability of at least five of the seeds germinating is at least 90%?
If X is a normal random variable with mean μ = 3 and standard deviation σ = a. P(X > 11) b. P(2-3|X > -5) 4, find
Q9. Let us assuming the voltage output of a microphone is a Gaussian random variable V with expected value Hy = 0 and standard deviation ơy = 5 V. The microphone signal is the input to a limiter circuit with cutoff value ±10 V. The random variable W is the output of the limiter: 10 -10 V 10. W = g(V) = V -10 10 -10 10 V From this example, find the following A. Find the PDF of W? B. Find the CDF of W?
Let X be a normally distributed random variable with mean u = 27 and standard deviation o = 2. Calculate P(X < 21). Calculate P(25
Assume that the readings at freezing on a bundle of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading less than -1.171°C.P(Z < − 1.171)=
Use Hypothesis Testing for variance.
1)Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -0.305°C and 1.619°C.P(−0.305<Z<1.619)= 2)Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading between -0.561°C and -0.461°C.P(−0.561<Z<−0.461)=P(-0.561<Z<-0.461)=

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Let X be a normal random variable with mean 33 and standard deviation 4.02. Find c such that P(33-c < X < 33+c)=0.515. Round your answer to 4 decimal places. и — с H+c