Let x be a continuous random variable with a standard normal distribution. Using the accompanying standard normal distribution table, find P(x ≥ 2.09). Click the icon to view the standard normal distribution table. P(x22.09) = (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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### Problem Statement:

Let \( x \) be a continuous random variable with a standard normal distribution. Using the accompanying standard normal distribution table, find \( P(x \geq 2.09) \).

#### Instructions:
1. Click the icon to view the standard normal distribution table.

   ![Standard Normal Distribution Table Icon](image link here)

---

### Solution:

\[ P(x \geq 2.09) = \_\_\_\_ \] (Round to four decimal places as needed.)

---

### Explanation:
To find the probability \( P(x \geq 2.09) \), follow these steps:

1. **Access the Standard Normal Distribution Table:**
   - Click the provided icon to view the table, which lists the cumulative probabilities of the standard normal distribution for different z-values (standard scores).

2. **Locate the Value:**
   - Locate the z-score of 2.09 in the body of the table. The table will help determine the cumulative probability up to that z-score.

3. **Calculate \( P(x \geq 2.09) \):**
   - Identify the value corresponding to \( P(x \leq 2.09) \) from the table.
   - Compute \( P(x \geq 2.09) \) by subtracting the cumulative value from 1 (since the total probability must equal 1).

4. **Round the Result:**
   - Ensure your final probability value is rounded to four decimal places.

By following these instructions, you can accurately determine the required probability for the given z-score using the standard normal distribution table.

---

*[Note: Ensure you understand the concepts of the standard normal distribution, z-scores, and how to use the z-table for cumulative probabilities to effectively solve problems like this.]*
Transcribed Image Text:### Problem Statement: Let \( x \) be a continuous random variable with a standard normal distribution. Using the accompanying standard normal distribution table, find \( P(x \geq 2.09) \). #### Instructions: 1. Click the icon to view the standard normal distribution table. ![Standard Normal Distribution Table Icon](image link here) --- ### Solution: \[ P(x \geq 2.09) = \_\_\_\_ \] (Round to four decimal places as needed.) --- ### Explanation: To find the probability \( P(x \geq 2.09) \), follow these steps: 1. **Access the Standard Normal Distribution Table:** - Click the provided icon to view the table, which lists the cumulative probabilities of the standard normal distribution for different z-values (standard scores). 2. **Locate the Value:** - Locate the z-score of 2.09 in the body of the table. The table will help determine the cumulative probability up to that z-score. 3. **Calculate \( P(x \geq 2.09) \):** - Identify the value corresponding to \( P(x \leq 2.09) \) from the table. - Compute \( P(x \geq 2.09) \) by subtracting the cumulative value from 1 (since the total probability must equal 1). 4. **Round the Result:** - Ensure your final probability value is rounded to four decimal places. By following these instructions, you can accurately determine the required probability for the given z-score using the standard normal distribution table. --- *[Note: Ensure you understand the concepts of the standard normal distribution, z-scores, and how to use the z-table for cumulative probabilities to effectively solve problems like this.]*
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