Let X and Y have the joint density function 1 f(x, y): x > 1, y > 1. Let U = XY and V = 3X/Y. (a) What is the joint density function of U,V? 1 fu,v(u, v) 2u?v (b) On what domain is this defined? u > 1 and

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Joint Density Function Analysis**

Let \( X \) and \( Y \) have the joint density function

\[
f(x, y) = \frac{1}{x^2 y^2},
\]

where \( x \geq 1, y \geq 1 \). Define \( U = XY \) and \( V = \frac{3X}{Y} \).

### (a) What is the joint density function of \( U, V \)?

The joint density function of \( U \) and \( V \) is given by:

\[
f_{U,V}(u, v) = \frac{1}{2u^2v}
\]

### (b) On what domain is this defined?

The domain is defined for \( u \geq 1 \) and \( \frac{3}{u} \leq v \leq 3 \).
Transcribed Image Text:**Joint Density Function Analysis** Let \( X \) and \( Y \) have the joint density function \[ f(x, y) = \frac{1}{x^2 y^2}, \] where \( x \geq 1, y \geq 1 \). Define \( U = XY \) and \( V = \frac{3X}{Y} \). ### (a) What is the joint density function of \( U, V \)? The joint density function of \( U \) and \( V \) is given by: \[ f_{U,V}(u, v) = \frac{1}{2u^2v} \] ### (b) On what domain is this defined? The domain is defined for \( u \geq 1 \) and \( \frac{3}{u} \leq v \leq 3 \).
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