Let /(x)= 5+ 6x Compute f(1) S'(1) s"(1) s"(1) sim(1) = sm(1) We see that the first term does not fit a pattern, but we also see thatf(1) for k 2 1. Hence we see that the Taylor series for f centered at 1 is given by S«) = 11+E (x- 1).
Let /(x)= 5+ 6x Compute f(1) S'(1) s"(1) s"(1) sim(1) = sm(1) We see that the first term does not fit a pattern, but we also see thatf(1) for k 2 1. Hence we see that the Taylor series for f centered at 1 is given by S«) = 11+E (x- 1).
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:5 + 6x
Let f(x) =
Compute
f(x)
f(1)
S'(x)
S'(1)
s"(x)
f"(1)
f"(x) =
s"'(1)
fim(x) =
fim(1) =|
fWx) =
fM(1)
We see that the first term does not fit a pattern, but we also see that f'W(1) =|
for k 2 1.
Hence we see that the Taylor series for f centered at 1 is given by
00
f(x) = 11 + E
(x – 1)*.
k=1
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