Let W(x, y) = F(u(x, y), v(x, y)), where F, u, and v are differentiable, and the following applies. F(0, 4) = 5 u(6, -1) = 0 u,(6, -1) = -8 v(6, -1) = 4 Vx(6, -1) = -4 Uy(6,-1) = 5 F(0, 4) = 2 Vy(6, -1) = 3 F(0, 4) = 7 Find W(6, -1), W,(6, -1) and W,(6, -1).. (Use the chain rule for the second and third.) W(6, -1) = W,(6, -1) = W,(6, -1) = You now have enough information to write down the linear approximation L(x,y) of the function W(x,y) at the point (х,у)%3 (6,-1). Use L(x,y) to find an approximate value for W(6.1,-0.8). W(6.1,-0.8) is approximately

Q: W(s, t) = F(u(s, t), v(s, t)), where F. u. and v are differentiable. If u (6,-6)= -2, u,(6, −6) = 3,…

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Q: W(s, t) = F(u(s, t), v(s, t)), where F. u. and v are differentiable. If u (6,-6)= -2, u,(6, −6) = 3,…

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