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Let w = sin(6x + y)²² ; x = 1³; y = 1²; z = 1-³. Find δω dt

Let w = sin(6x + y)²² ; x = 1³; y = 1²; z = 1-³. Find δω dt

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
дw Let w = sin(6x + y5)&z'; x = 15; y = 1; z = 1−3. Find . dt -30t os(6t−5 + r10)er' +1019 cos(6t−5 + +10)erh -12t−13 cos(6t5 + 110)er= −30t−4 cos(6t−5 + r10)er' +109 cos(6t−5 + 110)ern −12+−12 sin(6t^5 +110) err −301−6 cos(6t−5 + 110)er'+1019 cos(6t−5 + 110)er* −12t−13 sin(6t−5 + r10) er* -301−5 cos(6t−5 + 110)er*+10xº cos(6t−5 + 110)erº _12t−12 sin(6t^5 + 110) er" = -12t→ cos(6t−5 + 110)er" +10rºcos(6r-5 + r10)er*_121-12 sin(6t→5 +110) er* оди д дш д дш дт дш д1 О дw dt = == =
Transcribed Image Text:дw Let w = sin(6x + y5)&z'; x = 15; y = 1; z = 1−3. Find . dt -30t os(6t−5 + r10)er' +1019 cos(6t−5 + +10)erh -12t−13 cos(6t5 + 110)er= −30t−4 cos(6t−5 + r10)er' +109 cos(6t−5 + 110)ern −12+−12 sin(6t^5 +110) err −301−6 cos(6t−5 + 110)er'+1019 cos(6t−5 + 110)er* −12t−13 sin(6t−5 + r10) er* -301−5 cos(6t−5 + 110)er*+10xº cos(6t−5 + 110)erº _12t−12 sin(6t^5 + 110) er" = -12t→ cos(6t−5 + 110)er" +10rºcos(6r-5 + r10)er*_121-12 sin(6t→5 +110) er* оди д дш д дш дт дш д1 О дw dt = == =
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