Let V=R². For (u₁, U₂), (v₁, v₂) € V and a € R define vector addition by (u₁, ₂) (V₁, V₂) = (U₁ + v₁1, u2+ v2 - 3) and scalar multiplication by a □ (u₁, 1₂) := (au₁ —a +1, au₂ – 3a +3). It can be shown that (V,B, D) is a vector space over the scalar field R. Find the following: the sum: (-6, 0) (9,2)=( the scalar multiple: 40 (-6,0) =( the zero vector: Oy =( the additive inverse of (x, y): B(x, y) =(

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Let V = R². For (u1, U2), (V1, V₂) ≤ V and a E R define vector addition by (u₁, U2) = (v₁, v₂) := (U₁ + V₁ − 1, U2 + v₂ − 3) and scalar multiplication
-
-
by a □ (u₁, U₂) := (au₁ — a + 1, au2 − 3a + 3). It can be shown that (V, , ) is a vector space over the scalar field R. Find the following:
the sum:
(-6, 0) (9,2)=(
the scalar multiple:
40 (-6,0) =(
the zero vector:
0₁=(
the additive inverse of (x, y):
=(x, y) =(
"
1)
Transcribed Image Text:Let V = R². For (u1, U2), (V1, V₂) ≤ V and a E R define vector addition by (u₁, U2) = (v₁, v₂) := (U₁ + V₁ − 1, U2 + v₂ − 3) and scalar multiplication - - by a □ (u₁, U₂) := (au₁ — a + 1, au2 − 3a + 3). It can be shown that (V, , ) is a vector space over the scalar field R. Find the following: the sum: (-6, 0) (9,2)=( the scalar multiple: 40 (-6,0) =( the zero vector: 0₁=( the additive inverse of (x, y): =(x, y) =( " 1)
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