Let V₁, V2, and v3 be vectors in a vector space V, and let T:V→ R³ be a linear transformation for which T(v₁)-(1,-1,2), T(v₂) - (0, 3, 2), T(v3) - (-3, 1, 2) Find T(3v₁ - 4v2+5v3). T(3v₁-4v2+5v3) - (

Q: 5. (2)(12)(22)= Your answer

A: We first multiply 2 and 12 (2)(12)(22)=2×12×22=(2×12)×22=24×22

Q: 3.9b + a3 + 27 - 3a2 + 5a3 - 2a2 + 2.1b + 7

A:

Q: 3a + 46° – 5 = 3 (6) +4(2) – 5 ? ||

A: Solution: The objective is to calculate the value

Q: Use the substitution method to evaluate V1-22dx

A:

Q: 9. If 4x(y+2) ソー3 O J6 4x(y+2) – 2x, y # 3 or -2, and x #0,2= ソ-3 y+2 A) B) C) 2 1/8112 28

A:

Q: (4 9a² -16

A:

Q: Compute the following. (a) P6, 2. (b) C6, 2. (c) P6, 6.

A: P(n,r)=n!n-r!C(n,r)=n!n-r!.r!

Q: 4 (-1)*- k² k=2 3k II

A: Simplify the product as follows. ∏k=24-1k×k23k3=-12×22323-13×32333-14×42343

Q: 3(z+5)=12

A:

Q: What is the least common multiple of 12 and 2? lcm (12,2)=(

A: Algebra

Q: 9.6 (4x 5) Add the following. ldentify NPVS X²-4x X8-X-6 4x-4 x8-x-6

A: We have to add the given functions.

Q: what is  c-2d

A: We have to find      value of c-2d

Q: 3y² + 5y - 8

A: The given quadratic equation is:  3y2+5y-8