Let Vi = x ℝ − 1 i ≤ x ≤ 1 i = − 1 i , 1 i for each positive integer i. Find each of the following. (Enter your answers using interval notation.) (a) ∪4i = 1Vi = (b) ∩4i = 1Vi = (c) Are V1, V2, V3, mutually disjoint? Explain. a.) Yes, because the intersection of the sets V1, V2, V3, ... is empty. b.) Yes, because no two of the sets V1, V2, V3, ... have any elements in common. c.) Yes, because the union of the sets V1, V2, V3, ... is empty. d.) No, because no two of the sets V1, V2, V3, ... are disjoint. e.) No, because the sets V1, V2, V3, ... are disjoint. (d) ∪ni = 1Vi = (e) ∩ni = 1Vi = (f) ∪∞i = 1Vi = (g) ∩∞i = 1Vi =
Let Vi = x ℝ − 1 i ≤ x ≤ 1 i = − 1 i , 1 i for each positive integer i. Find each of the following. (Enter your answers using interval notation.) (a) ∪4i = 1Vi = (b) ∩4i = 1Vi = (c) Are V1, V2, V3, mutually disjoint? Explain. a.) Yes, because the intersection of the sets V1, V2, V3, ... is empty. b.) Yes, because no two of the sets V1, V2, V3, ... have any elements in common. c.) Yes, because the union of the sets V1, V2, V3, ... is empty. d.) No, because no two of the sets V1, V2, V3, ... are disjoint. e.) No, because the sets V1, V2, V3, ... are disjoint. (d) ∪ni = 1Vi = (e) ∩ni = 1Vi = (f) ∪∞i = 1Vi = (g) ∩∞i = 1Vi =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.6: Inequalities
Problem 79E
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Question
Let
Vi =
x ℝ
−
≤ x ≤
=
−
,
for each positive integer i. Find each of the following. (Enter your answers using interval notation.)1 |
i |
1 |
i |
1 |
i |
1 |
i |
(a)
∪4i = 1Vi =
(b)
∩4i = 1Vi =
(c) Are V1, V2, V3, mutually disjoint? Explain.
a.) Yes, because the intersection of the sets V1, V2, V3, ... is empty.
b.) Yes, because no two of the sets V1, V2, V3, ... have any elements in common.
c.) Yes, because the union of the sets V1, V2, V3, ... is empty.
d.) No, because no two of the sets V1, V2, V3, ... are disjoint.
e.) No, because the sets V1, V2, V3, ... are disjoint.
(d)
∪ni = 1Vi =
(e)
∩ni = 1Vi =
(f)
∪∞i = 1Vi =
(g)
∩∞i = 1Vi =
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