Let V be an inner product space over F. If F = R, prove that 1 llu 1 + v|| ² −— —-|| u — v||²2. If F = C, prove that (u, v) = (u, v) = = ||u + v||² + | || u + iv||² — ||u — v||² — ||u — iv||²2. - (2) Equations (2) and (3) are called the polarization identities, and they show how the inner product on V can be recovered from the norm.
Let V be an inner product space over F. If F = R, prove that 1 llu 1 + v|| ² −— —-|| u — v||²2. If F = C, prove that (u, v) = (u, v) = = ||u + v||² + | || u + iv||² — ||u — v||² — ||u — iv||²2. - (2) Equations (2) and (3) are called the polarization identities, and they show how the inner product on V can be recovered from the norm.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Let V be an inner product space over F. If F = R, prove that
(u, v) = ||1u + v||²³ − ||1u — v||²2.
If F = C, prove that
(u, v)
1
=
= || u + v||²³ + ² ||u + iv||² − −| ||u — v|| ² — — ||u — iv||²2.
-
-
(2)
(3)
Equations (2) and (3) are called the polarization identities, and they show how
the inner product on V can be recovered from the norm.
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