Let V be a finite-dimensional inner product space. A linear operator U on V is called a partial isometry if there exists a subspace W of V such that ||U(x)|| = ||x|| for all x EW and U(x) = 0 for all x € W¹. Observe that W need not be U-invariant. Suppose that U is such an operator and {V₁, V2, ..., Uk} is an orthonormal basis for W. Prove the following results. (b) {U(v₁), U(v₂),..., U(Uk)} is an orthonormal basis for R(U).

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Let V be a finite-dimensional inner product space. A linear operator U
on V is called a partial isometry if there exists a subspace W of V
such that ||U(x)|| = ||x|| for all x Є W and U(x) = 0 for all x € W¹.
Observe that W need not be U-invariant. Suppose that U is such an
operator and {V₁, V2, ..., Uk} is an orthonormal basis for W. Prove the
following results.
(b) {U(v₁), U(v₂),..., U(Uk)} is an orthonormal basis for R(U).
Transcribed Image Text:Let V be a finite-dimensional inner product space. A linear operator U on V is called a partial isometry if there exists a subspace W of V such that ||U(x)|| = ||x|| for all x Є W and U(x) = 0 for all x € W¹. Observe that W need not be U-invariant. Suppose that U is such an operator and {V₁, V2, ..., Uk} is an orthonormal basis for W. Prove the following results. (b) {U(v₁), U(v₂),..., U(Uk)} is an orthonormal basis for R(U).
(c) There exists an orthonormal basis for V such that the first
k columns of [U], form an orthonormal set and the remaining
columns are zero.
-
(d) Let {w₁, W2, . ‚w;} be an orthonormal basis for R(U)± and ß =
{U(v₁), U(v₂),..., U(Vk), W₁, ..., W;}. Then 3 is an orthonormal
basis for V.
Transcribed Image Text:(c) There exists an orthonormal basis for V such that the first k columns of [U], form an orthonormal set and the remaining columns are zero. - (d) Let {w₁, W2, . ‚w;} be an orthonormal basis for R(U)± and ß = {U(v₁), U(v₂),..., U(Vk), W₁, ..., W;}. Then 3 is an orthonormal basis for V.
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