Let us modify Computer Exercise C4 in Chapter 8 by using voting outcomes in 1990 for incumbents who were elected in 1988. Candidate A was elected in 1988 and was seeking reelection in 1990; voteA90 is Candidate A's share of the two-party vote in 1990. The 1988 voting share of Candidate A is used as a proxy variable for quality of the candidate. All other variables are for the 1990 election. The following equations were estimated, using the data in VOTE2: voteA90 = 75.71 + .312 prtystrA + 4.93 democA (9.25) (.046) -929 log(expendA) – 1.950 log(expendB) (.684) n = 186, R = .495, R = 483, (1.01) (.281) %3D and voteA90 = 70.81 + .282 prtystrA + 4.52 democA (1.06) (10.01) (.052) -.839 log(expendA) – 1.846 log(expendB) + .067 voteA88 (.687) n = 186, R² = .499, R² = .485. (.292) (.053) (i) Interpret the coefficient on voteA88 and discuss its statistical significance. (ii) Does adding voteA88 have much effect on the other coefficients?
Let us modify Computer Exercise C4 in Chapter 8 by using voting outcomes in 1990 for incumbents who were elected in 1988. Candidate A was elected in 1988 and was seeking reelection in 1990; voteA90 is Candidate A's share of the two-party vote in 1990. The 1988 voting share of Candidate A is used as a proxy variable for quality of the candidate. All other variables are for the 1990 election. The following equations were estimated, using the data in VOTE2: voteA90 = 75.71 + .312 prtystrA + 4.93 democA (9.25) (.046) -929 log(expendA) – 1.950 log(expendB) (.684) n = 186, R = .495, R = 483, (1.01) (.281) %3D and voteA90 = 70.81 + .282 prtystrA + 4.52 democA (1.06) (10.01) (.052) -.839 log(expendA) – 1.846 log(expendB) + .067 voteA88 (.687) n = 186, R² = .499, R² = .485. (.292) (.053) (i) Interpret the coefficient on voteA88 and discuss its statistical significance. (ii) Does adding voteA88 have much effect on the other coefficients?
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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