Let U c C be an open set. A function f: U → C is analytic if for every 20 € U there is a disk D(20,e) CU and a sequence (Cn) in C such that for all z e D(zo, e), f(2) = Cn(2 – 20). %3D n=0 Prove that if U is open and connected, V CU is open, f:U → C is analytic and satisfies flv = 0, then f = 0. (That is, any analytic function that vanishes on an open set vanishes everywhere. It's not necessary for the homework, but you can make this stronger by replacing V with any subset of U that has an accumulation point in U.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Let U c C be an open set. A function f: U → C is analytic if for
every 20 € U there is a disk D(20,e) CU and a sequence (Cn) in C such that for all
z e D(zo, e),
f(2) = Cn(2 – 20).
%3D
n=0
Prove that if U is open and connected, V CU is open, f:U → C is analytic and
satisfies flv = 0, then f = 0. (That is, any analytic function that vanishes on an open
set vanishes everywhere. It's not necessary for the homework, but you can make this
stronger by replacing V with any subset of U that has an accumulation point in U.)
Transcribed Image Text:Let U c C be an open set. A function f: U → C is analytic if for every 20 € U there is a disk D(20,e) CU and a sequence (Cn) in C such that for all z e D(zo, e), f(2) = Cn(2 – 20). %3D n=0 Prove that if U is open and connected, V CU is open, f:U → C is analytic and satisfies flv = 0, then f = 0. (That is, any analytic function that vanishes on an open set vanishes everywhere. It's not necessary for the homework, but you can make this stronger by replacing V with any subset of U that has an accumulation point in U.)
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