Let {u₁, 2,...} be an orthonormal set in a Hilbert space H and (kn) be a sequence in K. If En|kn| <∞o, then by 8.1, the series En knun converges in H. But the condition En kn<∞ is not necessary for the convergence of the series knun in H. In fact, as we have seen above, Σ kn2<∞o is a necessary and sufficient condition for such a convergence. For example, if kn = 1/n for n = 1,2,..., then En knl is divergent, but n knun ccnverges in H, since Στη || <00. Request explain how.
Let {u₁, 2,...} be an orthonormal set in a Hilbert space H and (kn) be a sequence in K. If En|kn| <∞o, then by 8.1, the series En knun converges in H. But the condition En kn<∞ is not necessary for the convergence of the series knun in H. In fact, as we have seen above, Σ kn2<∞o is a necessary and sufficient condition for such a convergence. For example, if kn = 1/n for n = 1,2,..., then En knl is divergent, but n knun ccnverges in H, since Στη || <00. Request explain how.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Request explain the underlined portion from the book "Functional Analysis" by BV Limaye
![Let {u₁, ₂,...} be an orthonormal set in a Hilbert space H and
(kn) be a sequence in K. If Σ kn<∞o, then by 8.1, the series
En knun converges in H. But the condition Σ kn<∞ is not
necessary for the convergence of the series knun in H. In fact,
as we have seen above, Σn kn2<∞o is a necessary and sufficient
condition for such a convergence. For example, if kn = 1/n for n =
1,2,..., then En knl is divergent, but knun ccnverges in H, since
Σn |kn|² <∞0.
Request explain how.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe15b7304-cc73-4505-92c3-23aa2fda4f71%2F82aef703-1157-4841-8116-2a700cf9cb49%2F5jbh3e3_processed.png&w=3840&q=75)
Transcribed Image Text:Let {u₁, ₂,...} be an orthonormal set in a Hilbert space H and
(kn) be a sequence in K. If Σ kn<∞o, then by 8.1, the series
En knun converges in H. But the condition Σ kn<∞ is not
necessary for the convergence of the series knun in H. In fact,
as we have seen above, Σn kn2<∞o is a necessary and sufficient
condition for such a convergence. For example, if kn = 1/n for n =
1,2,..., then En knl is divergent, but knun ccnverges in H, since
Σn |kn|² <∞0.
Request explain how.
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