Let U = {0, 1,2, ...,9}, A = {1, 2, 5, 8, 9}, B = {0, 1, 3, 4}, and C (AU B) nC = AU (Bn C) = A – (B – C) = B – (An C) = %3D C – (A U B) = %3D (A n B) U C =
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Set Operation:
- Union: It is denoted by symbol. Let's take two sets A & B, then contains all the elements which are present in set A or B or both.
- Intersection: It is denoted by symbol. Let's take two sets A & B, then contains all the elements which are present in set A and B both.
- Difference: It is denoted by symbol. Let's take two sets A & B, then contains all the elements which are present in set A but not in B.
- Complement: Let's take a set A, then contains all the elements which are present in the universal set not in the A.
Roaster Notation of Set: The set is represented in roaster notation by listing all the elements within braces {} and separated by comma(,).
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- C++ programming It has been observed by management that some faculty member at the university demonstrates a lackadaisical attitude toward work. They seldom go to class yet at the end of each month they receive full salary. Management has decided that GHs 200, 300, 400, and 500 will be deducted from a faculty’s salary if he/she offends once, twice, third time and forth time respectively in a month. This means that if a faculty member offends once in a month GHs 200 will be deducted, if a faculty member offends twice in a month, GHs 500 (i.e. 200+300) will be deducted, if a faculty member offends three times in a month GHs 900 (i.e.200+300+400), will be deducted and if a faculty member offends four times in a month GHs 1,400 (i.e. 200+300+400+500). Assuming all faculty members are on a flat salary rate of GHs 2500. a. Write a program to request for the names of four faculty members and number times he/she has absented him/herself from class. One of them should have absented him/herself…13. Factorial Implementation What is incorrect with the following implementation of factorial: def factorial(n): return n* factorial(n-1) Pick ONE option Nothing is wrong The return value should be n+ factorial(n-1) The return value should be factorial(n-1) * factorial(n-2) ) A base case is missing Clear Selection loxituC Programming Language (Code With C Programming Language) Problem Title : Visible Trees There is a legend about a magical park with N × N trees. The trees are positioned in a square grid with N rows (numbered from 1 to N from north to south) and N columns (numbered from 1 to N from west to east). The height (in metres) of each tree is an integer between 1 and N × N, inclusive. Magically, the height of all trees is unique. Bunga is standing on the northmost point of the park and wants to count the number of visible trees for each Column. Similarly, Lestari is standing on the westmost point of the park and wants to count the number of visible trees for each Row. A tree X is visible if all other trees in front of the tree X are shorter than the tree X. For example, let N = 3 and the height (in metres) of the trees are as follows6 1 87 5 32 9 4 On the first column, Bunga can see two trees, as the tree on the third row is obstructed by the other trees. On the second column, Bunga can see…
- Python Knapsack: you are carrying a knapsack with capacity to hold a total of weight C. You are selecting among n items with values A={a1, a2, ... , an} and associated weights W={w1, w2, ... , wn}. Here the weights and values are all positive. You wish to maximize the total value of the items you select not exceeding the given weight capacity, example, maximize sum_{a in A} such that sum_{w in W} <= C. Note that you can only select your items once. In Python, create function DP_K (C, A, W) as stated above. Input an array to the function to hold the backtrace. What is the best set of items for C = 30, A = [40, 110, 100] and w = [20, 30, 40]? This can be shown using auxiliary printing function.Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxJSON Response example when code = BAHRAIN as follows: { "Country": "Bahrain", "Tenps"il ("day": "SUNDAY", "temp"i {"day": "HONDAY", "temp": 35), ("day": "TUESDAYr, "teng": 39), ("day": "WEDNESDAY", "tenp": 37),. ("day"i "THURSDAY", "tenp": 35), ("day"i "FRIDAV", "temp": 34), ("day": "SATURDAY", "teng": 37) 1. Implement find Templ ) function as follows: Sample Eample This function will be called whenever the user change the value of the pull-down menu. This function should contact Ve the Web Service API, sending the selected country code, to Co display the information (country, daily temperatures in the week and average weekly temperature) inside the div tag whose id -result as shown in the example on the right. Country ahraln In addition, the country name and the average temperatures should be saved as one JS object inside an array in a local storage. Whenever new request is made, the countrylaverage will be saved and added to the array inside the local storage (duplicates is allowed).…
- Write assignment statements for the following: Assign a value of 1 to between if n is in the range -k through +k, inclusive; otherwise assign a value of 0 Assign a value of 1 to uppercase if ch is an uppercase letter; otherwise, assign a value of 0. Assign a value of 1 to divisor if m is a divisor of n; otherwise, assign a value of 0.L et D= { s, d, b}, E= { c, k}, G= { a, k }, U={a, b, c, d, k, s} DUE=نقطة واحدة Let A = {a; b; c; d} and R= {(a; a); (b; c); (c; b); (d; d)} then R is Transitive Equivalent not transitive