Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true. a. P (tzto) = .025, where df = 11 b. P (tzto) = .01, where df = 18 c. P (tsto) = .005, where df = 6 d. P (tsto) = = .05, where df = 13 Click the icon to view the table of critical values of t. a. The value of to is 2.201. b. The value of to is 2.552. c. The value of to is
Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true. a. P (tzto) = .025, where df = 11 b. P (tzto) = .01, where df = 18 c. P (tsto) = .005, where df = 6 d. P (tsto) = = .05, where df = 13 Click the icon to view the table of critical values of t. a. The value of to is 2.201. b. The value of to is 2.552. c. The value of to is
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 94E
Related questions
Question
![Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true.
a. P(tzto) = .025, where df = 11
b. P (tzto)
= .01, where df = 18
c. P (tsto)
= .005, where df = 6
d. P (tsto) = .05, where df = 13
Click the icon to view the table of critical values of t.
a. The value of to is 2.201 .
b. The value of to is 2.552.
c. The value of to is.
...](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2910e309-4023-42bb-9437-090123672c12%2F81fb11df-a286-44aa-9100-c0b0ae6bef7d%2Fujk125_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Let to be a specific value of t. Use the table of critical values of t below to find to-values such that following statements are true.
a. P(tzto) = .025, where df = 11
b. P (tzto)
= .01, where df = 18
c. P (tsto)
= .005, where df = 6
d. P (tsto) = .05, where df = 13
Click the icon to view the table of critical values of t.
a. The value of to is 2.201 .
b. The value of to is 2.552.
c. The value of to is.
...
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1: t- distribution table is used.
(a). degree of freedom (df) =11
P(t) = 0.025 gives
= 2.20099
(b). df is 18
P(t) = 0.01 gives
= 2.55238
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