Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Let there be three charges whose locations are given with respect to a coordinate system - Charge q1 = 54 µC is located at P (0, –24), Charge 2 = 27 µC is located at P2 (16, –40.0) and Charge q3 = 2 µC is located at P3 (26, 0). All the coordinates have units in centimeters. a) Find the position vector that points from P2 to P3. b) Find the electric force on 2 due to q3 only. c) Find the net electric force on 92 due to both q1 and 93.

Let there be three charges whose locations are given with respect to a coordinate system - Charge q1 = 54 µC is located at P (0, –24), Charge 2 = 27 µC is located at P2 (16, –40.0) and Charge q3 = 2 µC is located at P3 (26, 0). All the coordinates have units in centimeters. a) Find the position vector that points from P2 to P3. b) Find the electric force on 2 due to q3 only. c) Find the net electric force on 92 due to both q1 and 93.

icon
Related questions
Question

Please help me in this

**Transcription with Explanations for Educational Website** --- Let there be three charges whose locations are given with respect to a coordinate system: - Charge \( q_1 = 54 \, \mu C \) is located at \( P_1 (0, -24) \). - Charge \( q_2 = 27 \, \mu C \) is located at \( P_2 (16, -40.0) \). - Charge \( q_3 = 2 \, \mu C \) is located at \( P_3 (26, 0) \). All the coordinates have units in centimeters. **Tasks:** a) Find the position vector that points from \( P_2 \) to \( P_3 \). b) Find the electric force on \( q_2 \) due to \( q_3 \) only. c) Find the net electric force on \( q_2 \) due to both \( q_1 \) and \( q_3 \). --- **Explanations:** This problem involves calculating forces between point charges using their spatial coordinates and given magnitudes. Follow these steps for each task: - **Position Vector Calculation (a):** Determine the vector from \( P_2 \) to \( P_3 \) by finding the difference in the \( x \)- and \( y \)-coordinates. - **Electric Force Calculation (b & c):** Use Coulomb's Law to calculate forces. The force between two charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Each task will help to understand vector arithmetic and applying physical laws to calculate interactions between charged particles.
Transcribed Image Text:**Transcription with Explanations for Educational Website** --- Let there be three charges whose locations are given with respect to a coordinate system: - Charge \( q_1 = 54 \, \mu C \) is located at \( P_1 (0, -24) \). - Charge \( q_2 = 27 \, \mu C \) is located at \( P_2 (16, -40.0) \). - Charge \( q_3 = 2 \, \mu C \) is located at \( P_3 (26, 0) \). All the coordinates have units in centimeters. **Tasks:** a) Find the position vector that points from \( P_2 \) to \( P_3 \). b) Find the electric force on \( q_2 \) due to \( q_3 \) only. c) Find the net electric force on \( q_2 \) due to both \( q_1 \) and \( q_3 \). --- **Explanations:** This problem involves calculating forces between point charges using their spatial coordinates and given magnitudes. Follow these steps for each task: - **Position Vector Calculation (a):** Determine the vector from \( P_2 \) to \( P_3 \) by finding the difference in the \( x \)- and \( y \)-coordinates. - **Electric Force Calculation (b & c):** Use Coulomb's Law to calculate forces. The force between two charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Each task will help to understand vector arithmetic and applying physical laws to calculate interactions between charged particles.
Expert Solution
steps

Step by step

Solved in 6 steps with 15 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer