Let the random variable X follow a standard normal distribution. If P(X < 70.75) = 0.75, what is 70.75 (a) 0.675 (b) 0.750 (c) 0.525 (d) 0.921 (e) None of the above
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Let X denotes the standard normal distribution
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- Q6. (10%) Figure below shows the mean values of the cash flows associated with some investment. The initial investment is known and is not a random variable. The other cash flows are independent random variables with Normal distributions. In each case the standard deviation of the cash flow is one quarter of the mean value (o=.25µ). Compute the mean and standard deviation of the NPW of the cash flow. Accept or reject the investment based on the expected value. Compute the probability that this investment yields a return greater than the MARR. The MARR is 10%. $1.000 S800 $600 $400 $200 Year 2. 3. $2,000Let X random variable distribute as normal N(-1, 0.25) then P(z > - 2.5) equal: a. 0.9987 b. 0.9938 c. 0.0062 d. 0.0013The average THC content of marijuana sold on the street is 10%. Suppose the THC content is normally distributed with standard deviation of 2%. Let X be the THC content for a randomly selected bag of marijuana that is sold on the street. a. What is the distribution of X? X - N( b. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 10.9. Round to 4 decimal places. c. Find the 64th percentile for this distribution. Round to 2 decimal places.
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- We can use the central limit theorem when n<30 provided the population follows a normal distribution.Draw a graph for the standard normal distribution. Label the horizontal axis at values of -3, -2, -1, 0, 1, 2, and 3. Use the table of probabilities for the standard normal distribution to compute the following probabilities. (Round your answers to four decimal places.) (a) P(z ≤ 1.5) (b) P(Z < 1) (c) P(1 sz s 1.5) (d) P(0The random variable X = weight of a randomly selected bag of chips can be modeled by a normal distribution with µ=11.75 ounces and σ=0.09 ounces Using the 68-95-99.7 rule, which of the following is correct?I. The probability that a randomly selected bag of chips weighs between 11.66 ounces and 11.93 ounces is about 0.815.II. P(X < 11.93)=0.997III. P(X≥ 11.84) =0.84Let x be a random variable representing dividend yield of bank stocks. We may assume that x has a normal distribution with = 3.3%. A random sample of 10 bank stocks gave the following yields (in percents). 5.7 4.8 6.0 4.9 4.0 3.4 6.5 71 5.3 6.1 The sample mean is x = 5.38%. Suppose that for the entire stock market, the mean dividend yield is u= 4.5%. Do these data indicate that the dividend yield of all bank stocks is higher than 4.5%?Use a = 0.01.2. Let Z be a random variable with a standard normal distribution. Calculate: P(Z ≥ 1.98)= ? P(Z <− 2.77)= ? P(−3.19 ≤ Z ≤− 3.03)= ? P(Z ≤ −0.15 or Z ≥ 0.99)= ? If P(Z < k)=0.14, then the value of k is:? If P(Z > k)=0.89, then the value of k is:? Note: Answer with at least 4 decimal placesIf the random variable X has a normal distribution with mean = 48 and standard deviation = 18, then P(1.2 ≤ X ≤ 4.8) is...SEE MORE QUESTIONS
