Let T be a linear operator on a finite-dimensional vector space V such that the characteristic polynomial f(t) of T splits. Prove that f(T) = To; i.e., prove that T satisfies its characteristic polynomial. (This is a special case of the Cayley-Hamilton theorem.) Hint: Show that if ß is a Jordan canonical basis for T, then S(T)(x) = 0 for each xe B.

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Let T be a linear operator on a finite-dimensional vector space V such that
the characteristic polynomial f(t) of T splits. Prove that f(T) = To; i.e.,
prove that T satisfies its characteristic polynomial. (This is a special case of
the Cayley-Hamilton theorem.) Hint: Show that if ß is a Jordan canonical
basis for T, then S(T)(x) = 0 for each xe B.
Transcribed Image Text:Let T be a linear operator on a finite-dimensional vector space V such that the characteristic polynomial f(t) of T splits. Prove that f(T) = To; i.e., prove that T satisfies its characteristic polynomial. (This is a special case of the Cayley-Hamilton theorem.) Hint: Show that if ß is a Jordan canonical basis for T, then S(T)(x) = 0 for each xe B.
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