Let sin 3x сos 13лу = sin 3x + cos 13Ty = T(x) of the tangent line at (0, 2), then evaluate T(13). be the equation of a curve in the xy-plane. Find the equation y = T(13) =
Let sin 3x сos 13лу = sin 3x + cos 13Ty = T(x) of the tangent line at (0, 2), then evaluate T(13). be the equation of a curve in the xy-plane. Find the equation y = T(13) =
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![Let
\[
\sin 3\pi x \cos 13\pi y = \sin 3\pi x + \cos 13\pi y
\]
be the equation of a curve in the \(xy\)-plane. Find the equation \(y = T(x)\) of the tangent line at \(\left(0, \frac{1}{26}\right)\), then evaluate \(T'(13)\).
\(T(13) = \_\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1467f162-7185-45ab-925a-2589d3c8cce7%2F445bd9f1-c93d-4927-a06a-1ff6d4e8cad0%2Fq2jat9p_processed.png&w=3840&q=75)
Transcribed Image Text:Let
\[
\sin 3\pi x \cos 13\pi y = \sin 3\pi x + \cos 13\pi y
\]
be the equation of a curve in the \(xy\)-plane. Find the equation \(y = T(x)\) of the tangent line at \(\left(0, \frac{1}{26}\right)\), then evaluate \(T'(13)\).
\(T(13) = \_\).
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