Let S(a, b) = {na + mb : n, m e Z}. Problem 0.1. If c is a common divisor of a and b then cs for all s e S(a, b) Problem 0.2. If s e S(a,b) then gcd(a, b)|s. Problem 0.3. If s e S(a, b) then sa e S(a, b) for all æ € Z
Let S(a, b) = {na + mb : n, m e Z}. Problem 0.1. If c is a common divisor of a and b then cs for all s e S(a, b) Problem 0.2. If s e S(a,b) then gcd(a, b)|s. Problem 0.3. If s e S(a, b) then sa e S(a, b) for all æ € Z
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The GCD of two integers is the largest positive integer that divides both the integers.
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