Let S be the portion of the cone with equation z² = x² + y² which lies between the planes z = 1 and z = 2, oriented so that the normal vectors point inward and upward. (a) Give S a parameterization of the form r(u, v), where (u, v) [a, b] × [c, d], making sure to be consistent with the orientation of S we want. (b) As you did in problem 2, use this parameterization to find the boundaries of S.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Certainly! Here is the transcription of the image text for an educational context:

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**3.** Let \( S \) be the portion of the cone with equation \( z^2 = x^2 + y^2 \) which lies between the planes \( z = 1 \) and \( z = 2 \), oriented so that the normal vectors point inward and upward.

**(a)** Give \( S \) a parameterization of the form \( \mathbf{r}(u, v) \), where \( (u, v) \in [a, b] \times [c, d] \), making sure to be consistent with the orientation of \( S \) we want.

**(b)** As you did in problem 2, use this parameterization to find the boundaries of \( S \).

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**(c)** Let \( \mathbf{F} \) be the vector field \( xy \, \mathbf{i} + z^2 \, \mathbf{j} - (x - z) \, \mathbf{k} \). Stokes' theorem relates the curl integral of \( \mathbf{F} \) over \( S \) to the circulation integral of \( \mathbf{F} \) along the boundary of \( S \). The surface in this problem has two boundaries which we can call \( C \) and \( C' \). This means that in this case, Stokes' theorem tells us that

\[
\iint_S \underline{\hspace{1cm}} \, dy \wedge dz + \underline{\hspace{1cm}} \, dz \wedge dx + \underline{\hspace{1cm}} \, dx \wedge dy = \int_C \underline{\hspace{1cm}} \, dx + \underline{\hspace{1cm}} \, dy + \underline{\hspace{1cm}} \, dz + \int_{C'} \underline{\hspace{1cm}} \, dx + \underline{\hspace{1cm}} \, dy + \underline{\hspace{1cm}} \, dz.
\]

Fill in the blanks, and describe \( C \) and \( C' \) geometrically. You do not have to evaluate the integrals.

--- 

Note: For effective learning, it may be helpful to explore visual aids such as diagrams of the cone and the surfaces
Transcribed Image Text:Certainly! Here is the transcription of the image text for an educational context: --- **3.** Let \( S \) be the portion of the cone with equation \( z^2 = x^2 + y^2 \) which lies between the planes \( z = 1 \) and \( z = 2 \), oriented so that the normal vectors point inward and upward. **(a)** Give \( S \) a parameterization of the form \( \mathbf{r}(u, v) \), where \( (u, v) \in [a, b] \times [c, d] \), making sure to be consistent with the orientation of \( S \) we want. **(b)** As you did in problem 2, use this parameterization to find the boundaries of \( S \). --- **(c)** Let \( \mathbf{F} \) be the vector field \( xy \, \mathbf{i} + z^2 \, \mathbf{j} - (x - z) \, \mathbf{k} \). Stokes' theorem relates the curl integral of \( \mathbf{F} \) over \( S \) to the circulation integral of \( \mathbf{F} \) along the boundary of \( S \). The surface in this problem has two boundaries which we can call \( C \) and \( C' \). This means that in this case, Stokes' theorem tells us that \[ \iint_S \underline{\hspace{1cm}} \, dy \wedge dz + \underline{\hspace{1cm}} \, dz \wedge dx + \underline{\hspace{1cm}} \, dx \wedge dy = \int_C \underline{\hspace{1cm}} \, dx + \underline{\hspace{1cm}} \, dy + \underline{\hspace{1cm}} \, dz + \int_{C'} \underline{\hspace{1cm}} \, dx + \underline{\hspace{1cm}} \, dy + \underline{\hspace{1cm}} \, dz. \] Fill in the blanks, and describe \( C \) and \( C' \) geometrically. You do not have to evaluate the integrals. --- Note: For effective learning, it may be helpful to explore visual aids such as diagrams of the cone and the surfaces
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