Let S= {a,b,c,d,e} with P(a)= .11, P(b) =.01, P(c)= .06 and P(d)= .08. If F is the event find {a,d,e}, find P(F).
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A: GivenP(E)=0.3P(F)=0.4P(F|E)=0.3
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A: Given that A and B are independent events. Thus, P(A n B) = P(A)P(B) = 0.5*0.6 = 0.3
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A: P(A) = 0.55. P(AC) = 0.45 P(B|A) = 0.75 P(B|Ac) = 0.09 P(B) = 0.453P(A|B) = ?
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A: P(E)^c is complement of P(E) P(E)+P(E)^c=1
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A: From the given information, N(NT)=134,767 and N(T)=77,789.
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A: GivenA and B are mutually exclusive eventsP(A)=0.2P(B)=0.7A and B are mutually exclusive…
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Q: Let A be the event that a flight from New York to San Fransisco arrives on time and let B be the…
A: GivenLet A be the event that flight arrive on timeP(B)=0.6P(A|B)=0.9P(A|Bc)=0.5
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A: Addition rule will applied here
Q: Suppose the probability of snow tomorrow is 0.3 while the probability of IU winning the basketball…
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- Don't know how to solveI am pulling one red ball out of one of three baskets. R= Red ball, B= Basket The chance I pull from the three baskets are the same. P(B1)=P(B2)=P(B3)= 0.33 The probability of pulling a red ball from each basket is given: P(RlB1)= 0.75, P(RlB2)= 0.6, P(RlB3)= 0.45 How do I find the probability of choosing a red ball?Suppose the probability of snow tomorrow is 0.4 while the probability of IU winning the basketball game tomorrow is 0.9. Assuming these events are independent, what is the probability that it snows and IU loses? (A) 1 (B) 0.04 (C) 0.06 (D) 0.4 (E) 0 (F) 0.54 (G) 0.36 (Н) 0.9 O B В C. O D O E OF OG
- Find the probability for P(y < 0 or y > 3) if y is distributed as N(1, 9)please you must answer part (d) (e) (f) thankResults from trials for a new pill for sleeping are given in this table. slept better (B) no improvement (N) sleeping pill (S) 144 21 sugar tablet (T) 55 89 What is the probability that the subjects slept better if they took the sleeping pill = P(B|S) ? What is the probability that the subjects took the tablet if they slept better = P(T|B)? Give your answer as a fraction.
- For the probability distribution, find b. P(y> 2) c. F(y = 6) d. P(y = 6) 0.05, 0.10, f(y)= 0.15, 0.20, X, y = -2 y = -1 y = 0 y = 1 y = 2Sasha volunteers in community events each month. She does not do more than five events in a month. She attends exactly five events 35% of the time, four events 25% of the time, three events 20% of the time, two events 10% of the time, one event 5% of the time, and no events 5% of the time. Find the probability that Sasha volunteers for less than three events each month. P(x<3)=Q. 2 The probability that a smoker who consumes over 20 cigarettes a day will suffer from chronic respiratory illness is 4 The 10 probability that he will suffer from heart disease is The 10 probability that he will suffer from at least one of these ailments is 6.5 10 (i) Find the probability that the smoker will suffer from both ailments. (ii) Find the probability that he will suffer from heart disease given that he suffers from chronic respiratory illness. (iii) Find the probability that he will suffer from chronic respiratory illness given that he suffers from heart disease. (iv) Are events "chronic respiratory illness" and "heart disease independent"?
- Find the probability P(Ec) if P(E)=0.17.q15A -Let A be the event that a flight from New York to San Fransisco arrives on time and let B be the event that it is a clear day in San Fransisco. Suppose that the probability of a clear day is P(B)=0.6.and the probability a plane arrives on time is P(A)=0.7. We also know that the probability a plane arrives on time on a cloudy day is P(A|B^C)=0.5, The events A and B are? Dependent Events Independent Events Disjoint Events All of the Above
