Let r(x) = f(g(h(x))), where h(1) = 2, g(2) = 3, h'(1) = 5, g'(2) = 3, and f(3) = 6. Find r'(1). r'(1) =

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Given the function \( r(x) = f(g(h(x))) \), where the following values are known: 
- \( h(1) = 2 \)
- \( g(2) = 3 \)
- \( h'(1) = 5 \)
- \( g'(2) = 3 \)
- \( f'(3) = 6 \)

Calculate \( r'(1) \).

To solve this, apply the chain rule for derivatives to find \( r'(x) \), which involves differentiating \( f(g(h(x))) \).

First, find the derivative \( r'(x) = f'(g(h(x))) \cdot g'(h(x)) \cdot h'(x) \).

Substitute \( x = 1 \) and use the given values:
1. Since \( h(1) = 2 \), substitute \( h(1) \) in \( g \)'s derivative: \( g'(2) = 3 \).
2. Since \( g(2) = 3 \), substitute \( g(2) \) in \( f \)'s derivative: \( f'(3) = 6 \).
3. Use \( h'(1) = 5 \).

Combine these results to find:
\[ r'(1) = f'(3) \cdot g'(2) \cdot h'(1) = 6 \cdot 3 \cdot 5 = 90. \]

Thus, \( r'(1) = 90 \).
Transcribed Image Text:Given the function \( r(x) = f(g(h(x))) \), where the following values are known: - \( h(1) = 2 \) - \( g(2) = 3 \) - \( h'(1) = 5 \) - \( g'(2) = 3 \) - \( f'(3) = 6 \) Calculate \( r'(1) \). To solve this, apply the chain rule for derivatives to find \( r'(x) \), which involves differentiating \( f(g(h(x))) \). First, find the derivative \( r'(x) = f'(g(h(x))) \cdot g'(h(x)) \cdot h'(x) \). Substitute \( x = 1 \) and use the given values: 1. Since \( h(1) = 2 \), substitute \( h(1) \) in \( g \)'s derivative: \( g'(2) = 3 \). 2. Since \( g(2) = 3 \), substitute \( g(2) \) in \( f \)'s derivative: \( f'(3) = 6 \). 3. Use \( h'(1) = 5 \). Combine these results to find: \[ r'(1) = f'(3) \cdot g'(2) \cdot h'(1) = 6 \cdot 3 \cdot 5 = 90. \] Thus, \( r'(1) = 90 \).
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