Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a+ bi : a, b e Z/5Z and i = v-1}. Show that R[i] is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].

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Chapter2: Second-order Linear Odes
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Let R = Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined
by R[i] = {a + bi : a, b e Z/5Z and i = v=1 }. Show that R[i] is not an integral
domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
Transcribed Image Text:Let R = Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a + bi : a, b e Z/5Z and i = v=1 }. Show that R[i] is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
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