Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a+ bi : a, b e Z/5Z and i = v-1}. Show that R[i] is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
Let R= Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined by R[i] = {a+ bi : a, b e Z/5Z and i = v-1}. Show that R[i] is not an integral domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Let R = Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined
by R[i] = {a + bi : a, b e Z/5Z and i = v=1 }. Show that R[i] is not an integral
domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a6de9c0-0dc9-496d-ac04-6f6e122e4a65%2F0a586d16-0e3c-440d-8ccd-e291e64f2af2%2Fsy3hs2f_processed.png&w=3840&q=75)
Transcribed Image Text:Let R = Z/5Z, the integers mod 5. The ring of Gaussian integers mod 5 is defined
by R[i] = {a + bi : a, b e Z/5Z and i = v=1 }. Show that R[i] is not an integral
domain (and hence not a field) by showing that 3+i is a zero-divisor in R[i].
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