Let R be the set of real numbers and let B be the collection of all intervals of the form [a, b), where a < b. Show that B is a base for a topology on R. (Recall that [a, b) = {x | a

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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The chapter is on Bases.
1. Let \(\mathbb{R}\) be the set of real numbers and let \(\mathcal{B}\) be the collection of all intervals of the form \([a, b)\), where \(a < b\). Show that \(\mathcal{B}\) is a base for a topology on \(\mathbb{R}\).

(Recall that \([a, b) = \{x \mid a \leq x < b\}\).)
Transcribed Image Text:1. Let \(\mathbb{R}\) be the set of real numbers and let \(\mathcal{B}\) be the collection of all intervals of the form \([a, b)\), where \(a < b\). Show that \(\mathcal{B}\) is a base for a topology on \(\mathbb{R}\). (Recall that \([a, b) = \{x \mid a \leq x < b\}\).)
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Consider the provided question,

Given that, R be the set of real numbers and B be the collection of all intervals of the form [a,b), where a < b.

Here, [a,b)=x|ax<b

We have to prove that B is base or basis for a topology on R.

(i) For any xR, x[x, x+1). So, R is union of all members of B.

(ii) Consider the interval [a,b) and [c,d), where a<b and c<d.

 

 

 

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