Let R be the region bounded by the curves xy² = 729 Set up an integral that computes the area A of R. (a) These curves intersect at (x, y) where (Give your answer as a comma separated list, for example: (a,b), (c,d) ...) (b) If we use horizontal slices for this area, we get nd = [²₁ C= = A = ,d= x = 90-y² f(y) dy + , f (y) = e= f ,g(y) = Put the integral for the leftmost section of the region first. No need to compute the area. [²9(y) dy

Q: 29) Find the area bounded by the curves y= In x, y = 2 In x and line x-e in the first quadrant.

A: I have given the answer in the next step. Hope you understand that

Q: Find the area bounded by the following curve and line: y=4/x , y²-4y+2x=5 and the line y=4

A:

Q: Determine the graph of the area between the curves bounded by y = -x² + 1 and x=y A B C D

A:

Q: Find the Area bounded by the curves y? = x and x = 2y – y².

A: Draw the graphs of the given curves and mark the intersection area.

Q: 6.(. Find the area of the region enclosed by the curves y = x² +1 and y = x +3.

A: I am solving this in step 2

Q: 2. Find the area bounded by y = x² - 2 and y = 2x + 1.

A:

Q: X 1) f(x) = x6 + 4x + 2 I NIX - 3) f(x) = ln(x5 - cos²x) 5) f(x)=xsin x + πT x5 -√x - In 3 3 2)…

A:

Q: 2. Find the area bounded by the curves y = x² and y = 2– x².

A: To find the area bounded by curves

Q: (b) the curve x = = y²-y-6 and the line x = = 2y + 4;

A: Given; x=y^2-y-6, x=2y+4

Q: √3n+1 2+√√n

A: Solve the following

Q: 4. Find the area of the region bounded by the curves x-y² = 0 and x+2y² = 6.

A: Hence, the area of the region bounded by the curves x-y2=0 and x+2y2=6 is 82 square units .

Q: If g(x) > (x) on the interval [a,b), then the area between the curves for as xs bis given by: O A.…

A: See step 2.

Q: Find the area bounded by the curve y? 4x and the lines x=1 and x=4.

A: Area bounded by a curve y=f(x) and the lines x=a and x=b is given by, A=∫abf(x)dx  We know, ∫xndx=…

Q: Find the area of the region bounded by the curve 2-4r and the lines x = 1 and x = 4. 63/2 square…

A: