Let p be the proportion of UCSD students who live on campus. You conduct a hypothesistest to test Ho: p = 0.7 against HA P0.7. The p-value for the test is 0.06. If you had considered theone-sided alternative HA :p> 0.7, the p-value would have been:a) 0.03.b) 0.03 or 0.97.c) 0.06.d) 0.97.e) None of the above.

Introduction: Denote p as the true population proportion.

Answered: Let p be the proportion of UCSD…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? A. Yes, the population does not need to be normally distributed. B. Yes, the population needs to be normally distributed. C. No, the population does not need to be normally distributed. D. No, the population needs to be normally distributed.
A simple random sample of size n= 16 is drawn from a population that is normally distributed. The sample mean is found to be x= 21.2 and the sample standard deviation is found to be s= 6.5. Determine if the population mean is different from 26 at the a= 0.05 level of significance. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of criticaltevalmes (a) Determine the null and alternative hypotheses. Ho H,: (Type integers or decimals. Do not round.) (b) Identify the test statistic. (Round to two decimal places as needed.) Approximate the P-value. The P-value is in the range (c) State the conclusion for the test.
You are given the following hypotheses:H0 : p = 0.9 HA : p not equal to 0.9 We know that the sample size is 1,429. For what sample proportion would the p-value be equal to 0.01? Assume that all conditions necessary for inference are satisﬁed
The commercial for the new Meat Man Barbecue claims that it takes 14 minutes for assembly. A consumer advocate thinks that the assembly time is lower than 14 minutes. The advocate surveyed 12 randomly selected people who purchased the Meat Man Barbecue and found that their average time was 13.5 minutes. The standard deviation for this survey group was 2.1 minutes. What can be concluded at the the a = 0.01 level of significance level of significance? You may assume the data are normally distributed.
The null hypothesis and the alternate hypothesis are: H0: The frequencies are equal.H1: The frequencies are not equal. Category f0 A 10 B 10 C 20 D 10 a. State the decision rule, using the 0.01 significance level. (Round your answer to 3 decimal places.) b. Compute the value of chi-square. (Round your answer to 2 decimal place.) c. What is your decision regarding H0?
In testing the hypotheses HO: p=0.5 vs. Ha: p does not equal 0.5, the test statistic is found to be 1.83. Which of the following in the correct p-value. A)1.9328 b).0672 c) .9964 d) .0336
The average wait time to get seated at a popular restaurant in the city on a Friday night is 13 minutes. Is the mean wait time greater for men who wear a tie? Wait times for 11 randomly selected men who were wearing a tie are shown below. Assume that the distribution of the population is normal. 12, 13, 13, 15, 13, 11, 14, 13, 15, 11, 15 What can be concluded at the the a = 0.01 level of significance level of significance?
7. In testing the hypothesis The test statistic is found to be Z = 2.03. Which of the following is the correct p-value? Họ: u = 35 Hạ: u > 35 %3D A. 0.9788 B. 0.0424 C. 0.0212 D. 1.9576 E. None of these
Question 2 A formal hypothesis test is to be conducted using the claim that the mean height of students is equal to 174.1 cm. State the null hypothesis. а. b. State the alternative hypothesis. с. What are the possible conclusions that can be made about the null hypothesis? d. Is it possible to conclude that “there is sufficient evidence to support the claim that the mean height of men is equal to 174.1 cm"?
Suppose a one sided test for a proportion resulted in a p-value of 0.06. What would the p-value be if the test were two tail test? Select one: A. It would still be 0.06. B. It would be 0.3. C. It would be 0.12. D. There is no way to calculate this without completely redoing the original test with a new alternative hypothesis.
The average fruit fly will lay 394 eggs into rotting fruit. A biologist wants to see if the average will change for flies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. Round your mean and standard deviation to three decimal places when doing these calculations. 376, 400, 402, 362, 386, 400, 368, 391, 399, 407, 384, 384, 371, 371 Download CSV What can be concluded at the the a = 0.01 level of significance level of significance?
A researcher claims that the incidence of a certain type of cancer is less than 5%. To test this claim, the a random sample of 4000 people are checked and 170 are determined to have the cancer. The following is the setup for this hypothesis test: Ho p 0.05 Ha :p< 0.05 In this example, the p-value was determined to be 0.015. come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) Select the correct answer below O The decision is to reject the Null Hypothesis. The conclusion is that there is enough evidence to support the claim o The decision is to fail to reject the Null Hypothesis. The conclusion is that there is not enough evidence to support the claim.

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