Let P be some predicate. Check the box next to each scenario in which Vn € N, P(n) must be true. (a) P(0) holds and for every natural number k > 0, if P(k) does not hold, then there is some natural number i < k such that P(i) does not hold. ✓(b) For every natural number k, if P(k) does not hold, then there is a smaller natural number i < k such that P(i) does not hold. ✔(c) For every natural number k > 0, if P(i) holds for every natural number i < k, then P(k) holds. (d) For every natural number k, if P(i) holds for every natural number i

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Let P be some predicate. Check the box next to each scenario in which Vn N, P(n) must be true.
P(0) holds and for every natural number k > 0, if P(k) does not hold, then there is some natural
number i < k such that P(i) does not hold.
✓(a)
✓(b)
For every natural number k, if P(k) does not hold, then there is a smaller natural number i < k such
that P(i) does not hold.
✔(c) For every natural number k > 0, if P(i) holds for every natural number i <k, then P(k) holds. x
(d) For every natural number k, if P(i) holds for every natural number i <k, then P(k) holds.
✓
Transcribed Image Text:Let P be some predicate. Check the box next to each scenario in which Vn N, P(n) must be true. P(0) holds and for every natural number k > 0, if P(k) does not hold, then there is some natural number i < k such that P(i) does not hold. ✓(a) ✓(b) For every natural number k, if P(k) does not hold, then there is a smaller natural number i < k such that P(i) does not hold. ✔(c) For every natural number k > 0, if P(i) holds for every natural number i <k, then P(k) holds. x (d) For every natural number k, if P(i) holds for every natural number i <k, then P(k) holds. ✓
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