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- Using given matrix P produced by Floyd2 Algorithm restore the path from v9 to V2 that has the minimum cost (shortest path). Hint: use path(r, q) function. P v1 "2 V3 v4 V5 V6 V7 8 90 19 v1 0 6 5 0 0 9 22 0 0 5 0 1 0 6 6 9 5 0 6 V3 6 9 0 6 9 9 9 9 0 v4 0 0 5 0 0 15 0 9 0 9 0 9 0 6 6 9 7 5 4. 3 0. 9 8 9 8 V6 17 18 19 8 8 0 0 2 7 8 5 0 1 0 0 9 0 8 0 8 8 0 9 8 0 0 8 9 0 3 0 6 7 02In this problem, we consider the class of n-dimensional axis-aligned boxes. Each function c in this class is specified by aset of 2n values ℓ1, . . . , ℓn and u1, . . . , un in [0, 1], which defines an axis-aligned n-dimensional box. Given an n-dimensionalinput vector x, c(x) is defined to be 1 (or ‘+’) if for every i ∈ {1, . . . , n} the i’th coordinate of x lies in [ℓi, ui]. Otherwise,c(x) is defined to be 0 (or ‘-’) .An example of a 2-dimensional axis-aligned box is shown in the figure below. (a) Let C be the class of n-dimensional axis-aligned boxes, and c ∈ C be the unknown target function. State an efficientalgorithm that takes as input an arbitrary set of points x1, x2, . . . , xm each a point in n-dimensional space, and theircorresponding labels c(x1), c(x2), . . . , c(xm), and outputs a function h ∈ C that is consistent with this data. Youralgorithm should run in polynomial time in m, n and facilitate answering part (b) below. Let D be an arbitrary, unknown distribution, and…
- Suppose a 2D bounding box is given by (≤ is "less than or equal to"): -1 ≤ x ≤ 1-10 ≤ y ≤ 10 Compute the new Bounding Box for the transformation given by the following matrix: (see section 9.4.4) 0.866 -0.5 0.5 0.866 Now enter the xmax for the new Bounding Box (round it to 3 decimal places, if needed).Let Tmn be a BTTB matrix with a generating function f(x, y) ∈C2π×2π. Let λmin(Tmn) and λmax(Tmn) denote the smallest and largest eigenvaluesof Tmn, respectively. Then we havefmin ≤ λmin(Tmn) ≤ λmax(Tmn) ≤ fmax,where fmin and fmax denote the minimum and maximum values of f(x, y), respectively. In particular, if fmin > 0, then Tmn is positive definite.give set of R(x): x < x^2 where the domain is Z