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Let n be any integer. If n=3k+5 for some integer k. Does 91 6n-3 No, because 6n-3= 18k+30-3 which is 9*(2k+3) No, because 9 is greater then 6n-3 Yes, because 6n-3= 18k+30-3 which is a multiple of 9 Yes, because 6n-3= 18k+30-3 which is a factor of 9

Let n be any integer. If n=3k+5 for some integer k. Does 91 6n-3 No, because 6n-3= 18k+30-3 which is 9*(2k+3) No, because 9 is greater then 6n-3 Yes, because 6n-3= 18k+30-3 which is a multiple of 9 Yes, because 6n-3= 18k+30-3 which is a factor of 9

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Let n be any integer. If n=3k+5 for some integer k. Does 91 6n-3 No, because 6n-3= 18k+30-3 which is 9*(2k+3) No, because 9 is greater then 6n-3 Yes, because 6n-3= 18k+30-3 which is a multiple of 9 Yes, because 6n-3= 18k+30-3 which is a factor of 9
Transcribed Image Text:Let n be any integer. If n=3k+5 for some integer k. Does 91 6n-3 No, because 6n-3= 18k+30-3 which is 9*(2k+3) No, because 9 is greater then 6n-3 Yes, because 6n-3= 18k+30-3 which is a multiple of 9 Yes, because 6n-3= 18k+30-3 which is a factor of 9
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