• Let (*n) and (Yn) be bounded sequences. Show that lim inf x, + lim inf yn < lim inf(xn + Yn) < lim inf xn + lim sup yn, n00 n-00 n00 n00 n00 Hint: for narts 2) and 3) VOL can take some proper subseguences and use part 1)
• Let (*n) and (Yn) be bounded sequences. Show that lim inf x, + lim inf yn < lim inf(xn + Yn) < lim inf xn + lim sup yn, n00 n-00 n00 n00 n00 Hint: for narts 2) and 3) VOL can take some proper subseguences and use part 1)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
How do you solve the third bullet point?

Transcribed Image Text:Let (xn) be a bounded sequence. Recall that
lim inf xn = sup inf xm =
sup inf{xn, &n+1,..}, lim sup an = inf sup am = infsup{rn, &n+1,• .}.
m>n
n m>n
n00
Show that L = lim inf xn is the smallest limit point of (xn), i.e., any subsequential limit of (xn) is not smaller
n-00
than L, and there is a subsequence that has L as its limit.
Remark: Similarly, lim sup xn is the largest limit point of (xn). This also shows that a sequence (xn) converges if
n00
and only if its lim sup and lim inf are equal.
• Let (xn) and (Yn) be bounded sequences and xn < Yn. Show that
lim inf xn <lim inf yn .
n00
n00
• Let (xn) and (Yn) be bounded sequences. Show that
lim inf xn + lim inf yn < lim inf(xn + Yn) < lim inf xn + lim sup Yn,
n00
n00
n00
n00
n00
Hint: for parts 2) and 3), you can take some proper subsequences and use part 1).}
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