Sample;Took_course;Did_not_take_course1;95;922;78;673;65;474;84;765;69;536;74;617;76;648;71;569;90;8510;96;9411;67;5012;93;8913;75;6214;99;9815;94;9116;79;6817;73;5918;91;8619;72;5820;89;83 An agency offers preparation courses for a graduate school admissions test to students. As part of an experiment to evaluate themerits of the course, 40 students were chosen and divided into 20 pairs in such a way that the members of any pair had similaracademic records. Before taking the test, one member of each pair was assigned at random to take the preparation course, whilethe other member did not take a course. The achievement test scores are contained in the accompanying table. Assuming that thedifferences in scores follow a normal distribution, test at the 5% level, the null hypothesis that the two population means are equalagainst the alternative that the true mean is higher for students taking the preparation course.Click the icon to view the data table.Click the icon to view the critical values of the Student's t distribution.Let μ₁ be the mean test scores for those who took the preparation course and let μ₂ be the mean test scores for those who didnot take the course. Determine the null and alternative hypotheses. Choose the correct answer below.A. Ho: H₁-H₂ = 0H₁: H₁-H₂ #0D. Ho: ₁-₂ <0H₁: μ₁ −μ₂ 20B. Ho: ₁-₂ 20H₁: H₁-H₂ <0O E. Ho: H₁-H₂>0H₁: μ₁ −μ₂ ≤0C. Ho: H₁ H₂ #0H₁: H₁-H₂ = 0F. Ho: ₁-₂ ≤0H₁: M₁-H₂>0

Let μ₁ be the mean test scores for those who took the preparation course and let µ₂ be the mean test scores for those who did not take the course. Determine the null and alternative hypotheses. Choose the correct answer below. OA. Ho: H₁-H₂ = 0 H₁: H₁-H₂0 D. Ho: H₁-H₂ <0 H₁: H₁-H₂ 20 OB. Ho: H₁-H₂ ²0 H₁: H₁-H₂ <0 E. Ho: ₁-₂0 H₁: H₁-H₂ ≤0 C. Ho: μ₁ −μ₂ #0 H₁: H₁-H₂ = 0 OF. Ho: H₁-H₂ ≤0 H₁: H₁-H₂>0