Let limx→a f(x) = ϕ and limx→a g(x) = γ. Then the following statements apply: a. limx→a (f(x) + g(x)) = ϕ + γ b. limx→a (f(x) − g(x)) = ϕ − γ c. limx→a (f(x) g(x)) = ϕ γ d. limx→a f(x)/g(x)=ϕ/γ provided γ ≠ 0 e. limx→a f(g(x)) = limx→γ f(x). Now I have the question , it is required to prove the statements only using the theorem given above: Take f, a and ϕ as in theorem. Show with the calculation rules that: a. for every k ∈ R holds limx→a kf(x) = kϕ; b. if P(x) is a polynomial is then limx→a P(x) = P(a); c. for every k ∈ Q holds limx→a(f(x))k = ϕk, provided k > 0.

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A:

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A:

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A: