Let Li be the line passing through the point P=(-1,-2,-3) with disection vector da-f-1,3,2], %3D and Let Lz be the line pogsing through e the Point P2 = (-12,18,-3) with didection vectos %3D [-2,-5,0]" dz= Find the shortest alistance d blw these and finel a point Q1 on L1 two lines and a Point G2 on Lz so that d(Q, Q2)=d. Use the squareroot Symbol '' where needed te give an exact value for your answe ŏ a d= ? =(?,?,?) %3D (?,?;?) %3D

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Please solve the attached applied linear algebra question as soon as possible.

G=> Let Li be the line passing through the point
Pi=(-1,-2,-3) with disection vector di f-l,;3,21,
->
and Let Lo be the line passing through the
Point P2 = (-12,18,-3) with dlidection vectos
%3D
2,-5,9
2.
Find the shortest alistance d blw these
two lines,
and finel a point G1 on L1
and a
point G2 on
on L2 so that
d(Q,Q2)=d. Use the sqjuareroot
%3D
symbol ?' where
needed te give an
exact
value foo your
answe.
d%= 7
@;= (?,?,,?)
Q
(?,?,?)
2=
Transcribed Image Text:G=> Let Li be the line passing through the point Pi=(-1,-2,-3) with disection vector di f-l,;3,21, -> and Let Lo be the line passing through the Point P2 = (-12,18,-3) with dlidection vectos %3D 2,-5,9 2. Find the shortest alistance d blw these two lines, and finel a point G1 on L1 and a point G2 on on L2 so that d(Q,Q2)=d. Use the sqjuareroot %3D symbol ?' where needed te give an exact value foo your answe. d%= 7 @;= (?,?,,?) Q (?,?,?) 2=
Hint to solve the
The shortest distance between these lines is along a straight line perpendicular to both lines. Since the two lines are not parallel, there is a unique solution for Q, and Q2.
To find Q, and Q, first find a vector n that is perpendicluar to both lines (usiing the cross product or by setting up a system of two equations using the dot product). You can then set up a
system of equations to find values a, b, c so that Pz+ad,+bn+cdz=P2 Use these values to find the desired points and distance.
Transcribed Image Text:Hint to solve the The shortest distance between these lines is along a straight line perpendicular to both lines. Since the two lines are not parallel, there is a unique solution for Q, and Q2. To find Q, and Q, first find a vector n that is perpendicluar to both lines (usiing the cross product or by setting up a system of two equations using the dot product). You can then set up a system of equations to find values a, b, c so that Pz+ad,+bn+cdz=P2 Use these values to find the desired points and distance.
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