Let k(x) = (4x²)g(x)h(x). Given the following table of values, find k' (1). -1 1 1 0 1 -4 0 2 1 -1 Provide your answer below: k'(1) = x h(x) g(x) h'(x) g'(x) 0 -3 3 3 0 3 3 0 -2 -2

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