Let In the current question we'll evaluate the integral of f(2) along two separate curves by using the method of parametrisation. Your evaluations must be given as complex numbers in correct Maple syntax. You may use a capital I for the complex number i, and Pi (with a capital P) for . You may use 1n for the natural logarithm of a positive real number, and you may use the exponential, trigonometric and hyperbolic functions: for example, 1n (21) and exp (Pi*1/22) and cos (23) and arctan (24/25). O==t(2+2) for t from 1 to 5 Oz=z+iz for a from 2 to 10 □ z=a+t(B-a) for t from 0 to 1 0 == Dy=zfor from 2 to 10 Oz from 2+2i to 10+ 10 Oz= (2+2) e10 for 0 from 1 to 5 Z= Oz (2+2)+1(8+81) for t from 0 to 1 f(2)= (a) Let C₁ be the straight line segment from 2 + 2 i to 10+ 10 i. Then C₁ can be parametrised as follows (select all correct answers): = (10 + 10 i) + (8 +81) for t from 0 to 1 Arg(z) f(z) dz Now evaluate the integral along C₁ of f(z), and enter your answer in the box. Answer: Jo₂

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Chapter2: Second-order Linear Odes
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Let
In the current question we'll evaluate the integral of f(z) along two separate curves by using the method of parametrisation. Your
evaluations must be given as complex numbers in correct Maple syntax. You may use a capital I for the complex number i, and Pi
(with a capital P) for . You may use 1n for the natural logarithm of a positive real number, and you may use the exponential,
trigonometric and hyperbolic functions: for example, ln (21) and exp (Pi*1/22) and cos (23) and arctan (24/25).
O==t(2+2i) for t from 1 to 5
Oz=x+iz for z from 2 to 10
Oz=a+t(B-a) for t from 0 to 1
Oz (10 + 10i) +t(8+8i) for t from 0 to 1
Oy=zfor æ from 2 to 10
0 z from 2+2i to 10+10i
Oz= (2+2i)ei for 0 from 1 to 5
Oz (2+2)+1(8+81) for t from 0 to 1
f(z) =
(a) Let C₁ be the straight line segment from 2 + 2 i to 10+10i. Then C₁ can be parametrised as follows (select all correct
answers):
Arg(z)
Answer:
Now evaluate the integral along C₁ of f(z), and enter your answer in the box.
Jo
f(z) dz=
Transcribed Image Text:Let In the current question we'll evaluate the integral of f(z) along two separate curves by using the method of parametrisation. Your evaluations must be given as complex numbers in correct Maple syntax. You may use a capital I for the complex number i, and Pi (with a capital P) for . You may use 1n for the natural logarithm of a positive real number, and you may use the exponential, trigonometric and hyperbolic functions: for example, ln (21) and exp (Pi*1/22) and cos (23) and arctan (24/25). O==t(2+2i) for t from 1 to 5 Oz=x+iz for z from 2 to 10 Oz=a+t(B-a) for t from 0 to 1 Oz (10 + 10i) +t(8+8i) for t from 0 to 1 Oy=zfor æ from 2 to 10 0 z from 2+2i to 10+10i Oz= (2+2i)ei for 0 from 1 to 5 Oz (2+2)+1(8+81) for t from 0 to 1 f(z) = (a) Let C₁ be the straight line segment from 2 + 2 i to 10+10i. Then C₁ can be parametrised as follows (select all correct answers): Arg(z) Answer: Now evaluate the integral along C₁ of f(z), and enter your answer in the box. Jo f(z) dz=
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