Question 5, 10.4.57 Anna's project for her introductory statistics course was to compare the selling prices of textbooks at two Internet bookstores. She first took a random sample of ten textbooks used that term incourses at her college, based on the list of texts compiled by the college bookstore. The prices of those textbooks at the two Internet sites are shown below. Perform a significance test comparing thepopulation mean prices.Site A $115 $79 $42 $137 $99 $29 $84 $99 $116 $69Site B $110 $79 $39 $129 $99 $29 $69 $99 $106 $66Let μd be the population mean difference in price. State the hypotheses to test whether the mean price is lower at one of the two Internet bookstores. Choose the correct answer below.A. Ho: Hd = 0 and H₂: Hd <0B. Ho: Hd #0 and H₂: Hd = 0C. Ho: Md= 0 and Ha: Hd >0D. Ho: Hd = 0 and Ha: Hd #0Determine the test statistic.t=(Round to three decimal places as needed.)

Given, Site A: 115, 79, 42, 137, 99, 29, 84, 99, 116, 69 Site B: 110, 79, 39, 129, 99, 29, 69, 99, 106, 66 Sample size, n = 10 (number of Site A and Site B) Assume Significance level α = 0.05 (If not given) Solution: Site A Site B diffrence d (A-B) d2 115 110 5 25 79 79 0 0 42 39 3 9 137 129 8 64 99 99 0 0 29 29 0 0 84 69 15 225 99 99 0 0 116 106 10 100 69 66 3 9 Total n = 10 ∑d = 44 ∑d2 = 432 Mean ,d¯ = ∑dn = 4410 = 4.4 Standard deviation, (sd): sd = 1n-1*(∑d2-(∑d)2n) sd = 110-1*(432-(44)210) sd = 5.1467 The Null and Alternative Hypothesis test is: H0: μd = 0 Ha: μd ≠ 0 Test statistics t: t = d¯-μsdn t = 4.4-05.146710 t = 2.7035 t = 2.704 therefore, test statistic t is 2.704 P-value: df = n-1 = 10 - 1 = 9 p value = 2*p(t < t calculated, df ) p value = 2*p(t < 2.704 , 9 ) p value = 0.0242 Since p value (0.02) < α (0.05) significance level. Therefore, we reject the null Hypothesis H0 and accept the alternative Hypothesis Ha. conclusion: There is sufficient evidence to conclude that the mean price is lower at one of the two internet bookstores.