Let H = Span(v1, V2, V3} and B= = {v1, v2, v3}. Show that B is a basis for H and x is in H, and find the B-coordinate vector of x for the given vector: 9 - 6 - 4 V3 6 X = 12 V2 - 9 - 22 - 2 - 2 - 8 Reduce the augmented matrix v, V2 V3 x to reduced echelon form. - 5 9 - 8 - 6 - 4 12 - 9 6 -7 - 22 -2 - 2 - 8 How can it be shown that B is a basis for H? O A. H is the Span(v1, v2, V3} and B= (V1, V2, V3) so therefore B must form a basis for H. O B. The augmented matrix is upper triangular and row equivalent to B x] therefore, B forms a basis for H. Oc. The first three columns of the augmented matrix are pivot columns and therefore B forms a basis for H. D. The augmented matrix shows that the system of equations is consistent and therefore B forms a basis for H. 7. CO II

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Chapter6: Linear Systems
Section6.3: Matrix Algebra
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How can it be shown that x is in H?
O A. The augmented matrix is upper triangular and row equivalent to B x
therefore x is in H because H is the Span{v1, V2, V3} and B= {v1, V2, V3}.
B. The first three columns of the augmented matrix are pivot columns and therefore x is in H.
O c. The augmented matrix shows that the system of equations is consistent and therefore x is in H.
O D. The last row of the augmented matrix has zero for all entries and this implies that x must be in H.
The B-coordinate vector of is x , =
Transcribed Image Text:How can it be shown that x is in H? O A. The augmented matrix is upper triangular and row equivalent to B x therefore x is in H because H is the Span{v1, V2, V3} and B= {v1, V2, V3}. B. The first three columns of the augmented matrix are pivot columns and therefore x is in H. O c. The augmented matrix shows that the system of equations is consistent and therefore x is in H. O D. The last row of the augmented matrix has zero for all entries and this implies that x must be in H. The B-coordinate vector of is x , =
Let H = Span{v,, V2, V3) and B= {v,, v2. V3}. Show that B is a basis for H and x is in H, and find the B-coordinate vector of x for the given vectors.
- 5
9
-8
- 6
4
6
X =
12
V1 =
V2
V3
6
- 22
- 2
-2
- 8
Reduce the augmented matrix
V1 V2 V3 x
to reduced echelon form
- 5
9 - 8
- 6
2 -4
12
-9
6
-7 - 22
4 - 2
-2
- 8
How can it be shown that B is a basis for H?
O A. His the Span(v1, V2, V3} and B= (v1, v2, V3) so therefore B must form a basis for H.
O B. The augmented matrix is upper triangular and row equivalent to B x therefore, B forms a basis for H.
O C. The first three columns of the augmented matrix are pivot columns and therefore B forms a basis for H.
O D. The augmented matrix shows that the system of equations is consistent and therefore B forms a basis for H.
Transcribed Image Text:Let H = Span{v,, V2, V3) and B= {v,, v2. V3}. Show that B is a basis for H and x is in H, and find the B-coordinate vector of x for the given vectors. - 5 9 -8 - 6 4 6 X = 12 V1 = V2 V3 6 - 22 - 2 -2 - 8 Reduce the augmented matrix V1 V2 V3 x to reduced echelon form - 5 9 - 8 - 6 2 -4 12 -9 6 -7 - 22 4 - 2 -2 - 8 How can it be shown that B is a basis for H? O A. His the Span(v1, V2, V3} and B= (v1, v2, V3) so therefore B must form a basis for H. O B. The augmented matrix is upper triangular and row equivalent to B x therefore, B forms a basis for H. O C. The first three columns of the augmented matrix are pivot columns and therefore B forms a basis for H. O D. The augmented matrix shows that the system of equations is consistent and therefore B forms a basis for H.
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