Let H be a connected planar graph with at least 3 vertices. Prove that f is greater than or equal to 2v-4, where v= number of vertices and f= faces of H. Show that for any integer v greater than or qual to 3, there exists a connected planar graph H that has v vertices and 2v-4 faces.

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A: Given - G be a simple graph with 11 vertices, each of degree 5 or 6 To Prove - G has at least 7…

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Q: 2n 4. Prove or disprove: for every n-vertex graph G, x(G) ≤ 2w(G) + a (G) (6 + 10.

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